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andreev551 [17]
3 years ago
13

How many significant figures? A) 1234500_______ B) 1230.0_____ C) 0.10220____ D) 34560000______ E) 0.0000302010_______ F) 0.0205

0______ G) 1.250 x 105_____
Chemistry
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

A) 5 sig figs

B) 4 sig figs

C) 4 sig figs

D) 4 sig figs

E) 5 sig figs

F) 3  sig figs

G) 5 sig figs

Explanation:

work for G- 1.250 x 105=  131.25

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What is the mass, in grams, 6.5 mol of sodium nitrate (nano3)? please show all work?
ladessa [460]
Mass is the property of a physical body and the resistance to acceleration when a net force is applied on the body.  
The atomic mass of sodium (Na) is = 22.98 
The atomic mass of nitrate (N) is = 14.00 
The atomic mass of oxygen (O) is = 15.99  
The sodium nitrate (NaNO3) consists of the atomic masses of Na+N+(O)3 = 85 grams  
Therefore, the mass of 6.5 mol of sodium nitrate is = 6.5 * 1 mol of NaNO3 
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PLS HURYYY ILL GIVE BRAINLIEST
ad-work [718]

The volume increases when the balloon temperature increases.

<u>Explanation:</u>

-10 F is converted into Kelvin as 249 K.

0°C is nothing but 0+ 273 = 273 K

And the room temperature is 25°C which is converted into Kelvin as 273 + 25 = 298 K.

249 K is below room temperature.

As per the Charles' law volume and temperature are directly proportional to each other, when the pressure of the gas remains constant.

V ∝ T

As the balloon temperature increases, the volume also increases.

5 0
3 years ago
DUE TOMORROW!!! 15 POINTS
Lunna [17]

Answer:

A. write balanced chemical equation (including states), for this process.

Explanation:

Almost all hydrocarbon 'burn' reactions involve oxygen; it's by far the most reactive substance in air.  

Hydrocarbon combustions always involve  

[some hydrocarbon] + oxygen --> carbon dioxide + steam.  

C6H6(l) + O2 (g)--> CO2 (g)+ H2O (g)

Balance carbon, six on each side:  

C6H6(l) + O2 (g)--> 6CO2 (g)+ H2O (g)

Balance hydrogen, six on each side:  

C6H6(l) + O2 (g)--> 6CO2(g) + 3H2O (g)

Now, we have fifteen oxygens on the right and O2 on the left.  

Two ways to deal with that. We can use a fraction:  

C6H6 (l)+ (15/2)O2 (g)--> 6CO2 (g)+ 3H2O (g)

Or, if you prefer to have whole number coefficients, double everything  

to get rid of the fraction:  

2C6H6 (l)+ 15O2 (g)--> 12CO2 (g)+ 6H2O (g)

With the SATP states thrown in...  

C6H6(l) + (15/2)O2(g) --> 6CO2(g) + 3H2O(g)

6 0
3 years ago
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