Answer:
m = 0.5556 mol/kg
Explanation:
The molality of any solution is calculated using the following expression:
m = moles solute / kg solvent (1)
So in order to calculate the molality of this solution, we need to calculate the moles of the glucose using the expression:
n = mass / molecular weight (2)
The molecular weight of glucose, can be calculated using the molecular mass of the atoms in the glucose:
C = 12 g/mol; H = 1 g/mol; O = 16 g/mol
the molecular weight is:
MW = (12*6) + (12*1) + (6*16) = 180 g/mol
Then, the moles of glucose:
moles = 50 / 180 = 0.2778 moles
The solvent in this case is water, and 500 g of water is 0.5 kg of water, so the molality is:
m = 0.2778 / 0.5
m = 0.5556 mol/kg
Answer:
your answer is 4 polar structure
<span>Each liquid boils only at a certain temperature, which is called its </span><span>Boiling Point
Water for example has a boiling point of 100 degrees Celsius.</span>
D. round is not a state of matter
1 L=.001 m^3=1.0E^-9 cm^3
