<u>Answer:</u>
For 2: The correct answer is grams of solute per 100 grams of solvent.
For 3: The correct answer is supersaturated.
For 4: the correct answer is the solubility decreases.
<u>Explanation:</u>
Solubility is defined as the property which refers to the ability of the solute that can be dissolved in a solvent. It is defined as the number of grams of solute per 100 grams of solvent.
Unsaturated solution is defined as the solution in which amount of solute that is dissolved in the solvent is less.
Saturated solution is defined as the solution in which no more solute can be dissolved in the given amount of solvent.
Emulsion is defined as the dispersion of one liquid in another liquid in which it is not soluble.
Supersaturated solution is defined as the solution in which solvent contains more amount of solute than the required amount. These solutions help in the process of crystallization.
When a crystal is added to a <u>supersaturated solution</u>, more and more particles come out of the solution and this process is known as crystallization.
According to the Henry's Law
The solubility of the gas in a liquid is directly proportional to the partial pressure of the gas.

With increase in the partial pressure, the solubility of the gas in liquid also increases and vice-versa.
Hence, the correct answer is the solubility decreases.
Answer:
P = 14.1 atm
Explanation:
Given data:
Mass of methane = 64 g
pressure exerted by water vapors = ?
Volume of engine = 24.0 L
Temperature = 515 K
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O + energy
Number of moles of methane:
Number of moles = mass / molar mass
number of moles = 64 g/ 16 g/mol
Number of moles = 4 mol
Now we will compare the moles of water vapors and methane.
CH₄ : H₂O
1 : 2
4 : 2/1×4 = 8 mol
Pressure of water vapors:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L
P = 338.25 atm.L/ / 24.0 L
P = 14.1 atm
Answer: 0.176 atm
Explanation: Solution attached:
Use Boyle's Law to find the new pressure of the gas.
P1V1 = P2V2
Derive for P2
P2 = P1V1 / V2
= 5.5 atm ( 4.8 L ) / 150 L
= 0.176 atm
<span>Ores are naturally occurring rocks that contain metal or metal compounds in sufficient amounts to make it worthwhile extracting them. For example, iron ore is used to make iron and steel.</span>