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Reil [10]
3 years ago
14

Referring back to question 6 above, in the TLC plate on the left the mobile solvent phase was ethyl acetate, in the plate on the

right it was 97% ethyl acetate and 3% methanol. Explain why the Rf values in the plate on the right are larger than those in the plate on the left. Your explanation must be in the terms of intermolecular forces, you are not allowed to only use the word "polarity".
Chemistry
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

Polarity is a measure of molecule's electrical charge which means that molecule or it's groups can have a dipole moment and also make hydrogen bonds.

Explanation:

So in terms of polarity methanol is more polar then ethyl acetate due to it's higher dipole moment and that it is a stronger hydrogen bond acceptor and also can be a hydrogen bond donor. So if we add methanol to the elutioning system it becomes more polar because and our compound moves faster on tlc due to methanol providing some more hydrogen bonds to it and increasing dipole-dipole interactions.

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the element carbon has two common isotopes: C-12 (12 U) AND C-13 (13.003355 U). IF THE AVERAGE ATOMIC MASS OF CARBON IS 12.0107
oksian1 [2.3K]

Answer:

The percent isotopic abundance of C- 12 is 98.93 %

The percent isotopic abundance of C- 13 is 1.07 %

Explanation:

we know there are two naturally occurring isotopes of carbon, C-12 (12u)  and C-13 (13.003355)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 13.003355

1-x for isotopes having mass 12

The average atomic mass of carbon is 12.0107

we will use the following equation,

13.003355x + 12 (1-x) = 12.0107

13.003355x + 12 - 12x = 12.0107

13.003355x- 12x = 12.0107 -12

1.003355x = 0.0107

x= 0.0107/1.003355

x= 0.0107

0.0107 × 100 = 1.07 %

1.07 % is abundance of C-13 because we solve the fraction x.

now we will calculate the abundance of C-12.

(1-x)

1-0.0107 =0.9893

0.9893 × 100= 98.93 %

98.93 % for C-12.

7 0
3 years ago
What is the electronegativity difference for a bond between potassium and iodine? A. 3.3 B. 4.6 C. 0.4 D. 1.7
user100 [1]
Iodine has an electronegativity of 2.5, and potassium has an electronegativity of 0.8, so the difference is:
2.5 - 0.8 = 1.7
7 0
3 years ago
Read 2 more answers
I need help please!Perform the following conversion. Make sure your answer has the correct number of significant digits.
Nuetrik [128]

Answer:

3220000

Explanation:

1kg=10^6 Gg

3.22×10^6

5 0
3 years ago
1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium
aniked [119]

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

M_1 =concentration of stock solution = 0.150 mol/L

V_1 = volume of stock solution = 10.0 ml

M_2 = concentration of dilute solution = ?

V_2 = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

0.150\times 10.0=M_2\times 100.0

M_2=0.015mol/L

As the concentration is less than the original concentration, the solution is termed as dilute.

7 0
3 years ago
Isotope b has a half-life of 3 days. a scientist measures out 100 grams of this substance. after 6 days has passed, the scientis
Brilliant_brown [7]
So half life is the time taken for a sample to decay to half its original mass, its a constant and applies to any original mass, it could be 5g or 1kg, it will take the same amount of time for the original mass to half. In this case the half life is 3 days.

After 3 days the sample will be at half its original mass, now 50g. 

Now we can treat the 50g as if its a new sample. After another 3 days (6 days in total) there will be half of 50g left, = 25g. 


6 0
3 years ago
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