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Reil [10]
2 years ago
14

Referring back to question 6 above, in the TLC plate on the left the mobile solvent phase was ethyl acetate, in the plate on the

right it was 97% ethyl acetate and 3% methanol. Explain why the Rf values in the plate on the right are larger than those in the plate on the left. Your explanation must be in the terms of intermolecular forces, you are not allowed to only use the word "polarity".
Chemistry
1 answer:
iren2701 [21]2 years ago
3 0

Answer:

Polarity is a measure of molecule's electrical charge which means that molecule or it's groups can have a dipole moment and also make hydrogen bonds.

Explanation:

So in terms of polarity methanol is more polar then ethyl acetate due to it's higher dipole moment and that it is a stronger hydrogen bond acceptor and also can be a hydrogen bond donor. So if we add methanol to the elutioning system it becomes more polar because and our compound moves faster on tlc due to methanol providing some more hydrogen bonds to it and increasing dipole-dipole interactions.

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1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?
RSB [31]

Answer : The number of molecules present in nitrogen gas are, 3.48\times 10^{13}

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

PV=nRT

where,

P = Pressure of N_2 gas = 1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm      (1 atm = 760 mmHg)

V = Volume of N_2 gas = 985 mL = 0.982 L    (1 L = 1000 mL)

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 0.0^oC=273+0.0=273K

Now put all the given values in above equation, we get:

(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K

n=5.78\times 10^{-11}mol

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains 6.022\times 10^{23} number of molecules.

As, 1 mole of N_2 gas contains 6.022\times 10^{23} number of molecules

So, 5.78\times 10^{-11} mole of N_2 gas contains (5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13} number of molecules

Therefore, the number of molecules present in nitrogen gas are, 3.48\times 10^{13}

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3 years ago
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