Answer:
I thinks it's stress caused by plate movement hope this helps
Answer:
1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br)
Explanation:
The covalent character always increases down the group, this is because ionic character decreases down the group and also electronegativity.
In the same way, Covalent character always decreases across a period because electronegativity increases across a period.
The higher the electronegativity values between the two atoms, the more ionic it will be.
The total amount that Staci had in hand is $200.00.
The ticket at that time costs $87.96.
One Tshirt costs, $30.00.
Now that she has paid ticket, she will deduct the ticket from the cash she has in hand, so as to know the amount she is remaining with.
Tha is, $200-$87.96 = $112.04.
∴ In hand Staci has $112.04 extra cash whereby she can purchase more t shirts.
To get the number of tshirt she can buy, she will divide the amount she has in hand by the amount per piece of t shirt.
For example, $112.04 / $30 = $3.73.
∴ Staci can only purchase threet shirts only at a total cost of $90 for all the t shirts which is $30 × 3 = $90.
Staci has excess of 22.04 after deducting ticket and the other amount she has used to purchase the extra t shirts.
That is, $112.04 - $90 = $22.04.
Answer:
Explanation:
To answer this question successfully, we need to remember that atoms are neutral species, since the number of protons, the positively charged particles, is equal to the number of electrons, the negatively charged particles. That said, we may firstly find an atom which has 3 electrons (and, as a result, 3 protons, as it should be neutral).
The number of protons is equal to the atomic number of an element. We firstly may have an atom with 3 protons and 3 electrons (atomic number of 3, this is Li).
Similarly, we may take the atomic number of 4, beryllium, and remove 1 electron from it. Upon removing an electron, it would become beryllium cation, 
.
We may use the same logic going forward and taking the atomic number of 5. This is boron. In this case, we need to remove 2 electrons to have a total of 3 electrons. Removal of 2 electrons would yield a +2-charged cation: 
.
