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Tcecarenko [31]
3 years ago
5

The ratio of cement : sand : aggregate in a mix of concrete is 1 : 3 : 3. Sang wants to make 112 kg of concrete. How much sand d

oes he need?
Mathematics
2 answers:
Kisachek [45]3 years ago
8 0

Answer: 48

Step-by-step explanation:

The share of sand in the mixture is 3/7

To make 112 kgs. of concrete, he will need

3/7 x 112 = 48 units of sand

morpeh [17]3 years ago
8 0

Answer:

<h2>48 kg</h2>

solution,

Ratio of cement:sand:aggregate

=1:3:3

Total of ratios=1+3+3

=7

Total concrete=112 kg

Amount of sand required:

\frac{ratio \: of \: sand}{total \: ratio}  \times amount \: of \: concrete \\  =  \frac{3}{7}  \times 112 \\  = 48 \: kg

Hope this helps...

Good luck on your assignment...

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