The answer is going to be 127% Hopes this helps :)
So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: 
Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: 
Now you can rewrite this as 
, however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is 
. Applying that here, we have 
. x^4 + 5x^2 - 36 is completely factored.
Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 
Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 
Now you can rewrite the equation as 
. 2x^2 + 9x - 5 is completely factored.
<h3><u>Putting it all together, your factored expression is
</u></h3>
I don’t know what you’re tying to say
I got 65 for my answer. Hope that helps!
Answer:
There were 26 students in his class and the teacher had 83 ml of the solution.
Step-by-step explanation:
Mr. Kohl has a "x" amount of solution, if he divides it by the number of students "n" he'll give each student 3 milliliters and have a left over of 5 milliliters. If the amount of solution Mr. Kohl had was "x + 21" then he'd be able to give each student 4 milliliters of the solution. From these informations we have:
x = 3*n + 5
(x + 21)/n = 4
x + 21 = 4*n
x = 4*n - 21
Now that we have two equations and two variables we can solve the system of equations, as seen bellow:
3*n + 5 = 4*n - 21
3*n - 4*n = -21 - 5
-n = -26
n = 26
x = 4*26 - 21 = 83 ml
There were 26 students in his class and the teacher had 83 ml of the solution.
