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qwelly [4]
2 years ago
13

Sharon paid a total of $25.52, which included sales tax on all the items. What tax rate did Sharon pay? Round the answer to the

nearest percent.
Mathematics
1 answer:
Alex787 [66]2 years ago
4 0

The answer would be 7%

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The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

                         P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

              P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

        P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]        

              P[X=3]*P[C1=1,C2=1,C3=1]  = P[X=3]*(P[C=1]^3)

- Thus, we have:

                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
2 years ago
Which of the following is not the same as postive 7​
shusha [124]
Am I suppose to be looking at a picture?
8 0
2 years ago
What is one effect of World Bank loans to developing countries?
matrenka [14]
One example is they help them develop projects
7 0
2 years ago
Find the length x and y please
Artemon [7]

Answer:

2

Step-by-step explanation:

To find the x-intercept using the straight-line equation, substitute y=0 and solve for x. To find the y-intercept, substitute x=0 and solve for y.

7 0
2 years ago
A market research team compiled the following discrete probability distribution, where X represents the number of automobiles ow
rodikova [14]

Answer:

The standard deviation of X is 0.7

Step-by-step explanation:

We are given the following distribution:

    x:     0        1         2       3    

P(x):    0.3     0.5     0.2     0.4

We have to find the standard deviation of X.

Formula:

E(x) = \displaystyle\sum x_iP(x_i)\\\\E(x) =0(0.3) + 1(0.5) + 2(0.2) + 3(0.4)\\\\E(x) = 2.1\\\\E(x^2) = \displaystyle\sum x_i^2P(x_i)\\\\E(x^2) =0(0.3) + 1(0.5) + 4(0.2) + 9(0.4)\\\\E(x^2) = 4.9\\\\Var(x) = E(x^2) - (E(x))^2 = 4.9-(2.1)^2 = 0.49\\\\\sigma(x) = \sqrt{Var(x)} =\sqrt{0.49} = 0.7

Thus, the standard deviation of X is 0.7

6 0
3 years ago
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