Four consecutive integers... n, n+1, n+2, n+3.
The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.
n(n+3)=2n(n+3)-4 perform indicated multiplications...
n^2+3n=2n^2+6n-4 subtract n^2 from both sides
3n=n^2+6n-4 subtract 3n from both sides
n^2+3n-4=0 factor
n^2-n+4n-4=0
n(n-1)+4(n-1)=0
(n+4)(n-1)=0, and since n>0
n=1
So the four numbers are 1, 2, 3, 4
check...
1(4)=2(1)4-4
4=8-4
4=4
There are 50 different possible debating teams that could be selected as obtained using COMBINATION.
Since there are EQUAL number of juniors and seniors ;
Then we have 5 of each.
Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION
since the team MUST contain 4 SENIORS and 2 JUNIORS
4 Seniors from 5 = 5C4 = 5
2 Juniors from 5 = 5C2 = 10
Hence, (5C4 * 5C2) = 5 * 10 = 50
Hence, there are 50 different possible debating teams that could be selected.
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Answer:
495 in
Step-by-step explanation:
The formula for the volume of a triangular prism is V = 
· w · h · l, where w represents with, l represents length, and h represents height. Using this and plugging in the values, we can solve.
V = · 5 · 11 · 18
V = 2.5 · 11 · 18
V = 27.5 · 18
V = 495
hope this helps :)
3(x+5)=8x~~~First we distribute (we multiply 3 by x and 3 by 5)
3x+15=8x~~~Remove 3x from both sides
-3x -3x
15=5x~~~~Turn this equation around so x is on the other side
5x=15~~~Divide by 5x
÷5x ÷5x
x=3
