For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
Be more specific I just need points
Answer:
<h2>7142.86 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>7142.86 moles</h3>
Hope this helps you
The molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
M1V1 = M2V2
Where;
- M1 = molarity of a base
- M2 = molarity of acid
- V1 = volume of base
- V2 = volume of acid
M1 × 200 = 50 × 5
200M1 = 250
M1 = 250/200
M1 = 1.25M
Therefore, the molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
Learn more about molarity at: brainly.com/question/12127540
