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prisoha [69]
3 years ago
6

What is the definition of Indirect Proportion Graph?

Chemistry
2 answers:
kykrilka [37]3 years ago
6 0

Answer: The graph of an inversely proportional relationship displays a vertical asymptote at the y-axis as the y value increases without bound as x gets closer and closer to zero (but is positive) and decreases without bound as x gets closer and closer to zero (but is negative)and a horizontal asymptote at the x-axis as y gets .

Explanation: I hope this helps UwU

charle [14.2K]3 years ago
4 0

Answer:

Explanation:

The graph of an inversely proportional relationship displays a vertical asymptote at the y-axis as the y value increases without bound as x gets closer and closer to zero (but is positive) and decreases without bound as x gets closer and closer to zero (but is negative)and a horizontal asymptote at the x-axis as y gets .

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Percent Composition and Determining Empirical And Molecular Formulas
raketka [301]

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)

3 0
2 years ago
A stone is dropped from the roof of a building; 2.00s after that, a second stone is thrown straight down with an initial speed o
Brut [27]
A) -0.5(9.8)*t^2 = -25(t-2) - 0.5(9.8)(t-2)^2 
-4.9t^2 = -25t + 50 - 4.9(t^2-4t+4) 
0 = -25t+50+19.6t - 19.6 
5.4t = 30.4 
t = 5.62962963 s 

b) h = -4.9(5.62962963)^2 
h = -155.2943759 
the building is 155.2943759 m high 

c) speed 0of first stone 
= at 
= 9.8*5.62962963 
= 55.17037037 m/s 
speed of second stone
= v + at
= 25+9.8*3.62962963 
= 60.57037037 m/s
7 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures.
VladimirAG [237]

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 =  96.1 g

Molar mass of Ca(NO3)2 =  164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

Therefore, # moles of Ca3(PO4)2 produced = 0.0589 * 1/3 = 0.0196 moles

Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g



7 0
3 years ago
Read 2 more answers
Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated
NeX [460]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

8 0
3 years ago
During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

7 0
3 years ago
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