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2 years ago

In this experiment, student groups ran repeated trials (5) and then averaged their data. ALL BUT ONE statement explains why

Chemistry

2 answers:

dezoksy [38]2 years ago

4 0

Answer:

<em>The answer was B) Repeated trials ensure the desired results to support a hypothesis</em>

Explanation:

<em>Here's why: Data supports a hypothesis or not. You do not conduct an experiment to ensure specific results.</em>

Colt1911 [192]2 years ago

3 0

Answer:

its B

Explanation:

trust me i had this in my usatestprep, also follow me on tiktok, its ultrasolos

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The magnetic field of an object exerts a force on any magnetic object around it.

11111nata11111 [884]

Answer: True

Explanation: this is true

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2 years ago

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Match each of the three descriptions of a volume to the appropriate metric unit of volume

tankabanditka [31]

A.) 1.
b.) 3
c.) 2
I hope this helps.

8 0

3 years ago

When aqueous solutions of calcium bromide and potassium carbonate are combined, solid calcium carbonate and a solution of potass

ladessa [460]

$K_2CO_3 + CaBr_2$ → $KBr + CaCO_3$ is the net ionic equation for this reaction.

<h3>What is an ionic equation?</h3>

An ionic equation is a synthetic equation where electrolytes are composed as separated particles.

$K_2CO_3 + CaBr_2$ → $KBr + CaCO_3$ is the net ionic equation for this reaction.

A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.

Learn more about ionic equation here:

brainly.com/question/16225321

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5 0

1 year ago

If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc

Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$

Molarity of $NaOH$ solution = 0.1165 M

Volume of $NaOH$ solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

$\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq$

( as acidity of NaOH is 1)

For end point: gram equivalents of acid = gram equivalents of base = $2.875\times 10^{-3}$

Mass of acid= $gram equivalents\times {\text {Equivalent mass}}$

$0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}$

${\text {Equivalent mass}}=83.16g$

Thus equivalent mass of the acid is 83.16 grams

5 0

2 years ago

What us a bond between a positive and a negative ion called

Nat2105 [25]

Static. Is the bond if u need 2 know

6 0

2 years ago