<span>work = force x distances </span>
<span>A - moving 2 newton's up 0.6 meter = 1.2 joules
B - moving 4 newton's up 0.6 meter = 2.4 joules
C - moving 6 newton's up 0.3 meter = 1.8 joules
D - moving 9 newton's up 0.3 meter = 2.7 joules
The greatest amount of work is in example D.
</span>
<span>
D is your answer. </span>
Answer:

Explanation:
Hello,
In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

Thus, solving for the moles of the acid, we obtain:

Then, by using the mass of the acid, we compute its molar mass:

Regards.
C :)
I know this is right, I learned about this last year so I would really appreciate a brainliest
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