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Troyanec [42]
3 years ago
10

Which bond type is found in ammonium chloride. Select one: a. metallic b. covalent c. ionic

Chemistry
2 answers:
posledela3 years ago
8 0

Answer:

\boxed{\sf c. \ ionic}

Explanation:

NH₄Cl is formed by an ionic bond between NH₄⁺ and Cl⁻ ions.

NH₄Cl (solid) ⇒ NH4⁺ (aqueous) + Cl⁻ (aqueous)

Flura [38]3 years ago
7 0

Answer:

ionic

Explanation:

In NH4Cl molecule, ionic bond is formed between NH4+ and Cl– ions, 3 covalent bonds are formed between N and three H atoms and one coordinate bond is formed between N and 1 H atom.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

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Draw the products formed from 2-methyl-1-pentene by sequences (1.) and (2.).
snow_lady [41]

Answer:

See explanation and image attached

Explanation:

The mechanism for both the hydroboration of 2-methyl-1-pentene and acid-catalyzed hydration are shown i the image attached to this answer.

The both processes involve addition reaction. Hydroboration  is similar to hydration but the orientation of addition is anti - Markovnikov in nature.

The acid-catalyzed hydration of  2-methyl-1-pentene yields a minor product and a major product. The major product is  an accordance with Markovnikov  rule as shown by the reaction mechanism. The minor product is anti - Markovnikov.

4 0
3 years ago
A chemist fills a reaction vessel with a 0.105g mercurous chloride Hg2Cl2 solid, 0.926 M mercury (I) (Hg2^2+) aqueous solution,
Hoochie [10]

Answer:

ΔG = 98.67 kJ/mol

Explanation:

Let' s consider the following reaction.

Hg₂Cl₂(s) → Hg₂²⁺(aq) + 2Cl⁻(aq)

The standard Gibbs free energy (ΔG°) for the reaction is:

ΔG° = 1 mol × ΔG°f(Hg₂²⁺(aq)) + 2 mol × ΔG°f(Cl⁻(aq)) - 1 mol × ΔG°f(Hg₂Cl₂(s))

where,

ΔG°f: standard Gibbs free energy of formation

ΔG° = 1 mol × (154.72 kJ/mol) + 2 mol × (-134.08 kJ/mol) - 1 mol × (-215.06 kJ/mol)

ΔG° = 101.62 kJ

This is standard Gibbs free energy change per mole of reaction.

The Gibbs free energy of the reaction (ΔG) can be calculated using the following expression.

ΔG = ΔG° - R.T.lnQ

where,

R: ideal gas constant

T: absolute temperature

Q: reaction quotient

ΔG = ΔG° - R.T.ln([Hg₂²⁺].[Cl⁻]²)

ΔG = 101.62 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) . (298.2 K) . ln [(0.926).(0.573)²]

ΔG = 98.67 kJ/mol

5 0
3 years ago
In what point of view does the narrator have unlimited knowledge and can describe every characters thoughts and interpret behavi
777dan777 [17]

Answer:

Third person

Explanation:

plz brainlest me and say thx with the thanks button.

7 0
3 years ago
Read 2 more answers
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor
jenyasd209 [6]

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we <u>convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles</u>, using its<em> molar mass</em>:

  • Molar mass of CsXeF₇ = 397.193 g/mol
  • 73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As <em>1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇</em>, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we <u>convert 0.184 moles of CsF to moles</u>, using the <em>molar mass of CsF</em>:

  • Molar mass of CsF = 151.9 g/mol
  • 0.184 mol * 151.9 g/mol = 27.9 g
4 0
3 years ago
Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °
timofeeve [1]

We know, change in temperature is given by :

T_2-T_1=\dfrac{q}{mC_p(Gold)}

Putting all given values, we get :

T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC

Hence, this is the required solution.

6 0
4 years ago
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