We are given
Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get

We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote


Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0

Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get
y=1
now, we can draw graph
Graph:
Answer:
-3/2
Step-by-step explanation:
We have to see where the point lies, check the x-axis from the graph.
(-3/2, 1/2)
x = -3/2
The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
A game board with 17 spaces. Start, green, green, star, quesiton mark, question mark, star, question mark, green, cat town, gree
erastova [34]
Answer:
Possibly the answer is 2 green spaces, 2 star spaces, 3 question mark spaces
Step-by-step explanation: