Answer:
Rebounce angle is 345°
Rebounce speed is 989.95m/s
Explanation:
Calculate the x component of the velocity of the bullet before impact by using the following relation:
Vbx= Vb Cos thetha
Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°
Substituting
Vbx = Cos15 ×1400 = 1352.30m/s
Calculate the y component using the relation:
Vby = Vo Sin theta
Vby = sin 15° × 1400
Vby = 362.35m/s
The rebounce angle = 360 - incidence angle
Rebounce angle =( 360 - 15)° = 345°
The rebound speed V' = Vby - Vbx
V' = (1352.30 - 362.35)m/s
V' = 989.95 m/s
An object at rest stays at rest and an object in motion<span> stays in </span>motion <span>with the same speed and in the same direction unless acted upon by an unbalanced force.
I hope this helps you </span>
Answer:
<em><u>Ohm's Law:</u></em>
------------------(1)
Where V is voltage, I is current and R is resistance.
Whereas,
P = I V --------------------(2)
Where P is power, I is current and V is Voltage.
<u>Putting (1) into (2)</u>
=> P = I (I R) [∴ V = I R]
=> P = I²R (Derived!)
Answer:
Bro where's the image?
Explanation:
First send the image and then ask the question dude
Reservoir i think. i’m not sure
