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nikklg [1K]
3 years ago
5

A cell phone is released from the top with the speed of 10ms what is the speed 3s after?

Physics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

30ms

Explanation:

you need to multiple the 10ms by 3s which gives you 30ms

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A rock is launched at angle theta=53.2∘ above the horizontal from an altitude of ℎ=182 km with an initial speed ????0=1.61 km/s.
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Answer:

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Explanation:

Let's start by finding the initial vertical speed.

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We want to know the speed of the rock when it is at an altitude of 91 km.

The total displacement of the rock from its starting position will thus be equal to -91 km

We can use this in the following equation:

s=u*t+\frac{1}{2} (a*t^2)

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Thus it takes 4.3918 seconds to reach the required altitude. We can now find the speed as follows:

V=U+at

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V = -42.24

Thus the rock's final speed at the required altitude will be 42.24 m/s.

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