3 years ago

A cell phone is released from the top with the speed of 10ms what is the speed 3s after?

Physics

1 answer:

sergeinik [125]3 years ago

6 0

Answer:

30ms

Explanation:

you need to multiple the 10ms by 3s which gives you 30ms

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$R^{2}=A^{2}+B^{2}+2ABCos(\alpha)\\ \\A^{2}=A^{2}+A^{2}+2*A*A*Cos(\alpha)\\\\0=A^{2}+2*A^{2}*Cos(\alpha)\\\\Cos(\alpha)=-\frac{A^{2}}{2*A^{2}}=-\frac{1}{2}\\\\\alpha =Cos(-\frac{1}{2})^{-1}=120\°$

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Have a nice day!

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