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expeople1 [14]
3 years ago
13

A rope exerts a 280 N force while pulling an 80 Kg skier upward along a hill inclined at 12o. The rope pulls parallel to the hil

l. The coefficient of friction between the skier and the hill is 0.15. If the skier starts from rest, determine her speed after moving 100 m up the slope.
Physics
1 answer:
user100 [1]3 years ago
4 0

Answer:

The speed of the skier after moving 100 m up the slope are of V= 25.23 m/s.

Explanation:

F= 280 N

m= 80 kg

α= 12º

μ= 0.15

d= 100m

g= 9,8 m/s²

N= m*g*sin(α)

N= 163 Newtons

Fr= μ * N

Fr= 24.45 Newtons

∑F= m*a

a= (280N - 24.5N) / 80kg

a= 3.19 m/s²

d= a * t² / 2

t=√(2*d/a)

t= 7.91 sec

V= a* t

V= 3.19 m/s² * 7.91 s

V= 25.23 m/s

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The friends are ready to try a problem. A battery has an emf of 12.0 V and an internal resistance of 0.05 Ω. Its terminals are c
Zanzabum

Answer:

Terminal voltage = 11.5 V

Power across load = 119.7 W

Power across internal resistance = 5.4 W

Power delivered by battery = 125.2 W

Explanation:

The current in the circuit is given by

I=\dfrac{E}{R+r}

where E is the emf of the battery, R us the load resistance and r is the internal resistance.

I=\dfrac{12}{1.1+0.05} = 10.43 \text{ A}

The terminal voltage is the potential difference across the load resistor.

V = I × R = 10.43 A × 1.1 Ω = 11.5 V

The power across any resistance is given by I^2R

For the load resistor,

P_L=10.43^2\times1.1 = 119.7 \text{ W}

For the internal resistance,

P_r=10.43^2\times0.05= 5.4\text{ W}

The power delivered by the battery is

P = P_L + P_r = 119.7 + 5.4 = 124.1 \text{ W}

This could also be found by

P = IE = 10.34\times12 = 125.2 \text{ W}

The discrepancy in both answers is due to the approximations. The second answer is better.

4 0
4 years ago
Audible limit of the sound wave
Sergio039 [100]

Answer:

20 hz - 20khz is the audible sound wave for humans

6 0
3 years ago
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Scorpion4ik [409]

Answer:

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3 0
3 years ago
Can someone plz help me with this I’m not understanding it and show work plz plz
Triss [41]

There are two forces acting on the teacher:

Force due to weight/gravity (Fg)

Force due to drag (Fd), which is a resistance opposite to the direction of motion. Think of an airplane flying through the sky: there will be air that tries to oppose the plane's direction of motion AKA air-resistance.

The force of gravity is always downward (the direction of gravity).

Like we said before, the force of drag is always opposite to the direction of motion. Since the teacher is falling down, the force of drag is exerted upward.

Look at the attached diagram. The teacher is the circle in the middle. The two arrows indicate the two forces and their directions.

Now let's look at numbers:

Fg = mg = 65kg * 9.81 m/s^2 = ??N

Fd = 320N

To find the "Net Force" we must add up all of the forces exerted on the teacher, BUT we have to take into account the direction of forces.

Let's define downward as our "positive" direction. Since downward is positive, that means our force due to gravity is positive = +Fg

But since our force due to drag is UPWARD that means our force is NEGATIVE = -Fd.

So our total net force is

\Sigma F = F_g - F_d

3 0
4 years ago
Please answer as fast as possible
sineoko [7]

Explanation:

the pressure is given by P=hpg

where h is height,p is density, g is 10m/s²

thus P= 0.05m•13.6x10³•10

P=6.8x10³ Hgmm

3 0
3 years ago
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