For this conversion you should know that 1 meter has 1000 millimeters and that 1s equals 1000000 micro seconds, then:
7mm/us * 1m/1000mm * 1000000us/1s = 7000 m/s
The mm are canceled just like the micro seconds and the result remains in m / s .
Therefore option A is correct
A) 7000m / s
Answer
From
V=Distance/time
The distance round a circular path or Object is 2πr
so
v=2πr/T
Making T(period) subject
T=2πr/v
where v is the linear velocity.
We don't have the velocity but we can get it.
The Moon and Earth exert gravitational force on each other and the Moon is kept in Orbit by Centripetal force.
Since the Moon doesn't fly out of Orbit... it must mean that the Gravitational force being exerted on it by the Earth is equal to its centripetal Force.
Equating Both (Fg=Fc)
Fg=GMm/R²
Fc=mv²/r
GMm/R² = mv²/R
Canceling out "m" and "r" on both sides
we're left with
V²=GM/R
V=√GM/R
Where M= Mass of Earth (5.98x10^24)
R=Distance between the center of earth and the Moon
G= Gravitational Constant(Value 6.67x10^-11)
V=√6.67x10^-11 x 5.98x10^24/(3.82x10^8)
V=1021.84meters per second.
Now
T=2πr/v
=2π x 3.82x10^8 / 1021.84
T=2.35x10^6seconds
Converting to days by dividing by(24 x 3600)
You have
T=27.2days approx.
✅✅✅
Answer:
3136
Explanation:
because you multiply 780 by 4 because if it has a constant speed meaning it will not change speed then you multiply it by 4 because it says in 4 hours ( I hope this helped)
Answer:
The answer to the question is
3340800 m far
Explanation:
To solve the question, we note that acceleration = 29 m/s²
Time of acceleration = 8 minutes
Then if the shuttle starts from rest, we have
S = u·t+0.5·a·t² where u = 0 m/s = initial velocity
S = distance traveled, m
a = acceleration of the motion, m/s²
t = time of travel
S = 0.5·a·t² = 0.5×29×(8×60)² = 3340800 m far
