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SOVA2 [1]
3 years ago
13

Am object of mass in a circular path of radius 100metres with the speed of 10metres/second.calculate the acceleration towards th

e center​
Physics
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

is 6

Explanation:

h

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Four objects are situated along the y axis as follows: a 2.09-kg object is at +2.97 m, a 2.93-kg object is at +2.53 m, a 2.57-kg
Tcecarenko [31]

Answer:

x = 0 m

y = 1.02 m

Explanation:

M1 = 2.09 kg

y1 = 2.97 m

M2 = 2.93 kg

y2 = 2.53 m

M3 = 2.57 kg

y3 = 0 m

M4 = 3.92 kg

y5 = -0.496 m

since all objects are situated on the Y-axis, this means the x coordinate of the center of mass is 0.

To find the y coordinate of the center of mass, we apply the equation below.

sum of moment of the objects about the origin = moment of the total mass of objects about the center of mass

M1.y1 + M2.y2 + M3.y3 + M4.y4 = Mt.Y

(2.09 x 2.97) + (2.93 x 2.53) + (2.57 x 0) + (3.92 x -0.496) = (2.09 + 2.93 + 2.57 + 3.92) Y

11.68 = 11.51 Y

Y = 11.68 / 11.51 = 1.02 m

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3 years ago
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Answer:

It does not hit the students face because the speed of the balloon slows down as energy is lost through thermal.

Explanation:

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3 years ago
When air resistance balances the weight of an object that is falling, the velocity _____.
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Decreases. Air resistance will slow a falling object to its terminal velocity, placing a limit on its acceleration. 
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Tamiko it's creating a list of characteristics traditionally associated with males in American society. which current characteri
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4 years ago
Read 2 more answers
To win the game, a place kicker must kick a
Dafna11 [192]

Answer:

1.86 m

Explanation:

First, find the time it takes to travel the horizontal distance.  Given:

Δx = 52 m

v₀ = 26 m/s cos 31.5° ≈ 22.2 m/s

a = 0 m/s²

Find: t

Δx = v₀ t + ½ at²

52 m = (22.2 m/s) t + ½ (0 m/s²) t²

t = 2.35 s

Next, find the vertical displacement.  Given:

v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s

a = -9.8 m/s²

t = 2.35 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13.6 m/s) (2.35 s) + ½ (-9.8 m/s²) (2.35 s)²

Δy = 4.91 m

The distance between the ball and the crossbar is:

4.91 m − 3.05 m = 1.86 m

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