Answer:
12 m/s
Explanation:
Using the continuity equation, which is an extension of the conservation of mass law
ρ₁A₁v₁ = ρ₂A₂v₂
where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.
ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow
A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)
A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)
v₁ = velocity of the fluid flowing at point 1 = 3 m/s
v₂ = velocity of the fluid flowing at The restriction = ?
ρ₁A₁v₁ = ρ₂A₂v₂
Becomes
A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)
(πD₁²/4) × 3 = (πD₂²/4) × v₂
3D₁² = D₂² × v₂
But
D₂ = (D₁/2)
And D₂² = (D₁²/4)
3D₁² = D₂² × v₂
3D₁² = (D₁²/4) × v₂
(D₁²/4) × v₂ = 3D₁²
v₂ = 4×3 = 12 m/s
Answer:
Movement of Electrons in opposite direction of the rotation of the pickup coil leads to the direction of Electrical energy ( Alternating current ).
Explanation:
For a Generator to generate electricity, Electrons that is found in the rotating coil of the Generator will experience some sort of force that makes them to start moving in a direction that is perpendicular to the direction of the rotating/pickup coil found in the Generator.
The conversion of mechanical energy (Rotation of the pickup coil ) to electrical energy takes place in the Generator
The generator makes an alternating current because electrons move in opposite direction of the rotating coil
In other to generate a Direct current using a generator we have to replace the slip rings with commutator.
Because it is not a good conductor of heat. so the answer is D.
Energy ,E= Sqrt{Energy intensity*Speed of light*Magnetic constant}
Where,
Energy intensity = 1.40 kW/m^2 = 1400 W/m^2
Speed of light = 3*10^8 m/s
Magnetic constant = 4pi*10^-7 H
Therefore,
E= Sqrt{1400*3*10^8*4*pi*10^-7} = 726.49 v/m
Now,
Emax = E*sqrt (2) = 726.49*Sqrt(2) = 1027.41 v/m
By Newton's second law, the apparent weight of rider coming at rest is <u>3548 N</u>.
According to formula, v = u + at
a = 39.2 m/
Force, F = ma
F = m(a+g)
F = apparent weight
m = mass, given = 65 kg
a = acceleration, given = 39.2 m/
g = 9.8 m/
Put these values in formula, F = m(a+g)
F = 65(39.2+9.8)
F = 3548 N
Therefore, the apparent weight of rider coming at rest is <u>3548 N</u>.
Learn more about apparent weight here:- brainly.com/question/24897276
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