Answer:
density d = 1.59 g/cm^3
The density of the rock is 1.59 g/cm^3
Explanation:
The density of an object can be derived by measuring its mass and then measuring its volume by submerging it in a graduated cylinder.
Density = mass/volume of water displaced
d = m/v ........1
Given;
mass m = 344 g
Volume of water displaced v = 216 cm^3
from equation 1, we can calculate the value of the density;
Substituting the given values;
d = 344/216 g/cm^3
d = 1.592592592592 g/cm^3
d = 1.59 g/cm^3
The density of the rock is 1.59 g/cm^3
Electrons can move from one atom to another.
When a lot of them are doing it at the same time,
you have an electric current.
We asked around here at Brainly, and nobody knows
what an "Msideus" is, but we all know that there aren't
any of them in atoms.
I am going to say
C. Energy contained in the nucleus of an atom
<span>In Ionic type of bonding, electrons are lost (more
protons than electrons and positive charge) or gained (more electrons than
protons, still a negative charge) by atoms, and the atoms are held together by
electrical attraction in the process. Covalent bondings are the sharing of electrons
as well as partial bondings. Covalent bondings’ electrons have the same charges
thus, there is no gaining or losing electrons in the process of sharing. Strong
bondings are applicable only to Hydrogen (H) atoms. </span>
Answer:
86.51° North of West or 273.49°
Explanation:
Let V' = velocity of boat relative to the earth, v = velocity of boat relative to water and V = velocity of water.
Now, by vector addition V' = V + v'.
Since v' = 6.10 m/s in the north direction, v' = (6.10 m/s)j and V = 100 m/s in the east direction, V = (100 m/s)i. So that
V' = V + v'
V' = (100 m/s)i + (6.10 m/s)j
So, we find the direction,Ф the boat must steer to from the components of V'.
So tanФ = 6.10 m/s ÷ 100 m/s
tanФ = 0.061
Ф = tan⁻¹(0.061) = 3.49°
So, the angle from the north is thus 90° - 3.49° = 86.51° North of West or 270° + 3.49° = 273.49°
