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uranmaximum [27]
2 years ago
7

Some one PLEASE help me

Mathematics
1 answer:
Korolek [52]2 years ago
5 0

Answer:

Search it up on goodle.

Step-by-step explanation:Its on goodle i thing

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How many terms are in this expression? 3n + 4b - 6.<br> A. 1<br> B. 2.<br> C. 3<br> D. 4
bogdanovich [222]

Answer:

I think it's

B)2

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2 years ago
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GIVING A BUNCH OF POINTS AND BRAINLIST!! PLEASE HELP ME FAST If h(x)=(f o g)(x) and h(x)=^4squareroot x+7 find g(x) if f(x)=^4 s
mojhsa [17]

i dont know this one i am soooorrrrryyy hope u get help quick

7 0
3 years ago
The two figures are congruent find the measure of the requested side or angle
antiseptic1488 [7]
You have not provided the figures, therefore, I cannot provide an exact answer.
However, I can helps you with the steps.

One important thing to note is that when writing statements of congruency, the order of writing the letters is very important. This is because each side/angle in the first figure would be congruent to the corresponding side/angle in the second.

Therefore, all you have to do in the above question is write the congruent figures and determine the corresponding congruent sides/angles

Example:
If we are given that triangle ABC is congruent to triangle DEF
This means that:
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Hope this helps :)
4 0
3 years ago
The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of
Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8  ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0
3 years ago
36.4<br> 14<br> 14<br> Find the area
weeeeeb [17]

Answer:7134.4

Step-by-step explanation: 36.4*14 is 509.6 and times 14 again is 7134.4

5 0
2 years ago
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