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mart [117]
3 years ago
7

Which expression is the best estimate of the product of 7/8 and 1/10

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
Multiply across 7/80
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Write an expression having only two terms that is equivalent to 2x – 3. Explain how you wrote the expression and how you can che
Andreas93 [3]

Answer:

4x-6

Step-by-step explanation:

Two times 2 equals 4 and 2 times 3 equals 6

5 0
3 years ago
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Solve the equation and give me how you solved it and the answer
Viktor [21]
Multiplying both sides by 3, we get (3/9)*(2m-16)=(2m+4). Next, we multiply both sides by 9 and expand to get 6x-48=18m+36. Subtracting 6x and 36 from both sides, we get 12x=-48-36=-84. After that, we divide both sides by 12 to get m=-7
4 0
3 years ago
Linda read 1/5 of a book on Friday and 2/7 of the book on Saturday. On Sunday she read 5/9 of the remaining pages. What fraction
insens350 [35]
Here, you just want to solve it by finding a common denominator.
1/5+2/7, because she read 1/5 and 2/7 of the book on separate days. The common denominator is 35.
7/35+10/35
=17/35
So that's how much of the book she read before Saturday.
Now it says that on Sunday she read 5/9 of the remaining pages, meaning:
1-17/35 should give us our answer
35/35-17/35=18/35
But since it says she read 5/9 of the remaining pages, we need to multiply 18/35 by 5/9 to get what 5/9ths of 18/35 is.
(18/35)(5/9)=2/7
Therefore she read 2/7ths of the book on Sunday.
3 0
3 years ago
I need help 6+2 plz answer for brain
Pavel [41]

Answer:

8

Step-by-step explanation:

i have 6 apples + 2 peers

4 0
3 years ago
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Suppose you know that Mr. and Mrs. Vincent have at most eight children. One day you happen to meet two girls who were the Vincen
lianna [129]

Answer:

The number of children are 4 out of which 3 are girls

Step-by-step explanation:

Data provided in the question:

P(Two randomly selected children are girls) = \frac{1}{2}

now,

let the number of children be 'n'

the number of girls be 'x'

thus,

P(Two randomly selected children are girls) = \frac{^xC_2}{^nC_2} = \frac{1}{2}

also,

^nC_r = \frac{n!r!}{(n-r)!}

thus,

\frac{\frac{x!2!}{(x-2)!}}{\frac{n!2!}{(n-2)!}} = \frac{1}{2}

or

\frac{x(x-1)}{n(n-1)}=\frac{1}{2}

or

2x(x-1) = n(n-1)

now

for x = 3 and n = 4

i.e

2(3)(3-1) = 4(4-1)

12 = 12

hence, the relation is justified

therefore,

The number of children are 4 out of which 3 are girls

3 0
3 years ago
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