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mart [117]
3 years ago
7

Which expression is the best estimate of the product of 7/8 and 1/10

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
Multiply across 7/80
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What is the domain of the relation?
Masja [62]

Answer:

the domain of the relation is C

5 0
3 years ago
Let​ R(x), C(x), and​ P(x) be,​ respectively, the​ revenue, cost, and​ profit, in​ dollars, from the production and sale of x it
sp2606 [1]

Answer:

P(x) = -0.004x^2 - 3.7x - 50

Step-by-step explanation:

We have to find profit P(x).

This can be easily found using a formula for Profit given the Revenue and Cost.

Profit = Revenue - Cost

P(x) = R(x) - C(x)

Given that:

R(x) = 6x

C(x) = 0.004x^2 + 2.3x + 50

to find P(x) we can simply subtract R(x) by C(x).

P(x) = R(x) - C(x)

P(x) = (6x) - (0.004x^2 + 2.3x + 50)

P(x) = 6x - 0.004x^2 - 2.3x - 50

and finally, after simplify this equation subtracting 6x by 2.3x.

this is the equation for the profit P(x)

P(x) = -0.004x^2 - 3.7x - 50

3 0
3 years ago
For how many positive values of n are both n3 and 3n four-digit integers?
AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

n^3 , 3^n our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0
3 years ago
2 1/3 divided by 1/4
zloy xaker [14]
Answer:

28/3

Step-by-step explanation:

2 1/3 divided by 1/4

We’ll start by 2 1/3

Multiply 3 x 2 and then add 1

3 x 2 = 6 + 1 = 7

Then add the denominator back

7/3

Now divide 7/3 by 1/4 like this!

Start by multiplying 4 by 7

4 x 7 = 28

Then multiply 3 by 1

3 x 1 = 3

Final results: 28/3
7 0
3 years ago
Using no digits other than 5 and 8, make a 6-digit number, that has the properties below. If it is impossible, write so. Of cour
Anna11 [10]
Since it's a multiple of 24, it has to be a multiple of the factors of 24.

Factors of 24:
2,3,4,6,8,12

You can use some of this knowledge to help create the number.
Since the # needs to be a multiple off 2, the last digit needs to be an 8

All numbers that are multiples of 3 have the property that all of their digits added together have to be a number that is evenly divisible by 3.

so your number will look like:
_ _ _ _ _ 8

so start trying combinations for the other 5 digits that give you a number that is a multiple of 3: 3,6,9,12,15, ect. If you can't find one, then it's impossible
5 0
3 years ago
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