Answer:
C. -11,325
Step-by-step explanation:
- To know the answer, is convenient to replace some values of "n" in the sum
![\sum_{(n=1)}^{150}[-1-(n-1)]](https://tex.z-dn.net/?f=%5Csum_%7B%28n%3D1%29%7D%5E%7B150%7D%5B-1-%28n-1%29%5D)
.
- The result would appear after adding up every value of the expression when n=1,2,3.....,150.
- When n=1, the expression takes the value of (-1):
![[-1-(1-1)]= (-1)-0=-1](https://tex.z-dn.net/?f=%5B-1-%281-1%29%5D%3D%20%28-1%29-0%3D-1)
. - When n=2, the expression takes the value of (-2):
![[-1-(2-1)]=-1-1=-2](https://tex.z-dn.net/?f=%5B-1-%282-1%29%5D%3D-1-1%3D-2)
. - Following this way, for every n, we will obtain -n, then, the sum will be:
. This sum can actually be expressed as 
, which is the result of solving the initial expression of the sum 
. - Finally, the sum of n=-1 to n=-150 equals -11,325.
Step-by-step explanation:
A= πr^2
r = √(A/π)
r = √(676π/π)
r = 26
C = 2πr
52π
= 163.36
Answer:
6 liters
Step-by-step explanation:
Given:
Renata's recipe for her famous Kale 'n' Clam Quencher calls for kale juice and clam juice in a 3:1 ratio.
If Renata pours 18 liters of fresh kale juice, how many liters of clam juice should she add to maintain this ratio?
Solution:
Ratio to be maintain by using kale juice and clam juice = 3 : 1 ( given)
Renata pours fresh kale juice = 18 liters
We have to calculate quantity of clam juice should be added to maintain this ratio:-
Let quantity of clam juice should be added = 
<u>Ratio to be maintain : : quantity of kale juice : quantity of clam juice</u>
By cross multiplication:
By dividing both sides by 3
Thus, 6 liters of clam juice should she add.
