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Alexeev081 [22]
3 years ago
7

Please I need urgent math help❤️❤️❤️

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:

there is nothing to help you on

castortr0y [4]3 years ago
5 0

Answer:

please where's the question

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What is the solution to the equation below round your answer to two decimal decimal places log4 x=2.1
Natali [406]

Answer:

B 18.38

Step-by-step explanation:

log4x = 2.1

logx/log4 = 2.1

logx = log(4) x 2.1

logx = 1.2643

x = antilog(1.2643)

x = 18.38 (to 2 d.p)

4 0
3 years ago
Read 2 more answers
Which of the following points is located in Quadrant IV?
kolbaska11 [484]

Answer:

(1,-4) is in quadrant 4

7 0
3 years ago
What is 11.15×20.78?
Novosadov [1.4K]
Simplify 15*20 to 300

11,300,78

I hope helped ^-^
6 0
3 years ago
Please look a the pic<br><br> also you need to find the area
iogann1982 [59]

Answer:

area of circle is 113.04 (i used 3.14 for pi) 3.14 x 6^2

area of square is 24 - 12 x 2 = 24

area of square without circle is 89.04 - 113.04 - 24 = 89.04

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Out of 100 students,15 passed in english, 12 passed in mathematics, 8 in science, 6 in english and mathematics, 7 in mathematics
Lyrx [107]
Because there are 4 students who passed in all subjects, we can say that only 2 students passed in English and Mathematics only, only 3 students passed in Mathematics and Science only, and no one passed in English and Science only.

Given that we have deduced the number of students who passed in two subjects, we can now solve for the number of students who passed only one subject. 
                English = 15 - (4 + 2 + 0) = 9
                Mathematics = 12 - (4 + 3 + 2) = 3
                Science = 8 - (4 + 3 + 0) = 1

1. In English but not in Science,
                    9 + 2 = 11
2. In Mathematics and Science but not in English
                    3 + 3 + 1 = 7
3. In Mathematics only 
                             = 3
3. More than one subject only
                   3 + 4 + 2 + 9 = 18

It will really be helpful if you draw yourself a Venn Diagram for this item. 
8 0
4 years ago
Read 2 more answers
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