The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.
Try doing this for the rest of them
Answer:
a. closed under addition and multiplication
b. not closed under addition but closed under multiplication.
c. not closed under addition and multiplication
d. closed under addition and multiplication
e. not closed under addition but closed under multiplication
Step-by-step explanation:
a.
Let A be a set of all integers divisible by 5.
Let
∈A such that 
Find 

So,
is divisible by 5.

So,
is divisible by 5.
Therefore, A is closed under addition and multiplication.
b.
Let A = { 2n +1 | n ∈ Z}
Let
∈A such that
where m, n ∈ Z.
Find 

So,
∉ A

So,
∈ A
Therefore, A is not closed under addition but A is closed under multiplication.
c.

Let
but
∉A
Also,
∉A
Therefore, A is not closed under addition and multiplication.
d.
Let A = { 17n: n∈Z}
Let
∈ A such that 
Find x + y and xy


So,
∈ A
Therefore, A is closed under addition and multiplication.
e.
Let A be the set of nonzero real numbers.
Let
∈ A such that 
Find x + y

So,
∈ A
Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.
Therefore, A is not closed under addition but A is closed under multiplication.
Answer:
Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:
Step-by-step explanation:
Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:
- Total de cartulina de María y Juan =

- Total de cartulina de María y Juan =

- Total de cartulina de María y Juan =

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:
- Total de cartulina de María y Juan =

- Total de cartulina de María y Juan =

- <u><em>Total de cartulina de María y Juan = </em></u>
<u><em /></u>
Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.
Just set up an equation comparing the two ratios and solve for the length, in this case x.
(10/19)=(6/x)
19/10=x/6
114/10=x
Answer= 11.4 feet for the length of the flower