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Mice21 [21]
3 years ago
14

In the figure, a square is inside another bigger square.

Mathematics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

x=a+b=4+3=7\ units

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

c^{2}= a^{2}+b^{2}

substitute

c^{2}= 4^{2}+3^{2}

c^{2}=25

c=5\ units

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

D^{2}= x^{2}+x^{2}

D^{2}= 7^{2}+7^{2}

D^{2}=98

D=9.9\ units

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

d^{2}= c^{2}+c^{2}

d^{2}= 5^{2}+5^{2}

d^{2}=50

d=7.1\ units

coldgirl [10]3 years ago
3 0

Answer:

its 7 and 10 in the blanks im pretty sure.

Step-by-step explanation:

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