Solve for x:
x^9 = n x
Subtract n x from both sides:
x^9 - n x = 0
Factor x and constant terms from the left hand side:
-x (n - x^8) = 0
Multiply both sides by -1:
x (n - x^8) = 0
Split into two equations:
x = 0 or n - x^8 = 0
Subtract n from both sides:
x = 0 or -x^8 = -n
Multiply both sides by -1:
x = 0 or x^8 = n
Taking 8^th roots gives n^(1/8) times the 8^th roots of unity:
Answer: x = 0 or x = -n^(1/8) or x = -i n^(1/8) or x = i n^(1/8) or x = n^(1/8) or x = -(-1)^(1/4) n^(1/8) or x = (-1)^(1/4) n^(1/8) or x = -(-1)^(3/4) n^(1/8) or x = (-1)^(3/4) n^(1/8)
4x+2x^2+3x-2x+7
First, you would combine like terms. In this case, you would add 4x and 3x then subtract 2x.
2x^2+5x+7
5x^2-2x+3+4x-2x^2
Once again, you must combine like terms. Subtract 2x^2 from 5x^2, then subtract 2x from 4x.
3x^2+2x+3
There you go! Hope it helps
-Lacy
Answer:
Step-by-step explanation:
x(3x+2)=16
3x²+2x-16=0
3x²+8x-6x-16=0
x(3x+8)-2(3x+8)=0
(3x+8)(x-2)=0
either 3x+8=0
x=-8/3(rejected as width can't be negative)
x-2=0
x=2
so width=2
length=3×2+2=6+2=8
