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Ivan
4 years ago
6

For which values of a the system 3−7x < 3x−7 ,1+2x < a+x has no solutions?

Mathematics
1 answer:
erica [24]4 years ago
8 0

Answer:

a= -infinity to 3

Step-by-step explanation:

Given

3 - 7x < 3x - 7

1+2x < a+x

Required

Determine the value of a such that the inequality has no solution

Considering the first inequality (<em>Solve for x)</em>:

3 - 7x < 3x - 7

Collect Like Terms

3 + 7 < 3x + 7x

10 < 10x

Divide both sides by 10

1 < x

Reorder

x > 1

This means that the least value of x is 2;

Substitute x=2 in the second equation

1+2x < a+x

1 + 2(2) < a + 2

1 + 4 < a + 2

5 < a + 2

Collect Like Terms

5 - 2 < a

3 < a

Reorder

a > 3

This means that the least value of a is 4

Hence;

<em>The values of a for which the system has no solution is -infinity to 3</em>

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