For the following reaction, find the value of Q and predict the direction of change, given that a 1L flask initially contains 2 moles S8, 2 moles SF6, and 2 moles F2. 1/8 S8 (s) + 3 F2 (g) ⇄ SF6 (g) Kc = 0.425
(A) Q = K, system is at equilibrium
(B) Q < K, reaction will make more reactants
(C) Q < K, reaction will make more products
(D) Q > K, reaction will make more reactants
(E) Q > K, reaction will make more products
1 answer:
Answer:
C) Q < K, reaction will make more products
Explanation:
1/8 S8(s) + 3 F2(g) ↔ SF6(g) ∴ Kc = 0.425 = [ SF6 ] / [ F2 ]³
∴ Q = [ SF6 ] / [ F2 ]³
∴ [ SF6 ] = 2 mol/L
∴ [ F2 ] = 2 mol/L
⇒ Q = ( 2 ) / ( 2³)
⇒ Q = 0.25
⇒ Q < K, reaction will make more products
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