Answer:
The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.
Explanation:
4 items being divided equally among 3 people
Answer:
Potential energy
Explanation:
A mountain climber at the peak of a mountain has potential energy.
The potential energy of a body is stored energy in a body. It is function of mass and position of the body.
Mathematically;
P.E = mgh
m is the mass
g is the acceleration due to gravity
h is the height
Answer:
[H⁺] = 6.083x10⁻⁴ M, [C₆H₅OO⁻] = 6.083x10⁻⁴ M, [C₆H₅OOH] = 3.98x10⁻³M, pH = 3.22
Explanation:
Data: we have 0.56 gr of benzoic acid, disolved in 1Lt of water. Kₐ = 6.4x10⁻⁵
M (molar mass) of BA (Benzoic Acid) = 122 g/mol
Then, the inicial concentration is 0.56/122 = 4.59x10⁻³ M
We should consider the equation once it reaches the equilibrium:
C₆H₅COOH ⇄ C₆H₅COO⁻ + H⁺
C - x x x
And, for the Kₐ:
Kₐ = [H⁺][C₆H₅COO⁻]/[C₆H₅COOH] = x²/(C-x) , where C = 4.59x10⁻³
Then: x² + Kₐx - KₐC = 0
x² + 6.4x10⁻⁵ - 2.9x10⁻⁷ = 0
Resolving this cuadratic equation (remember to use Baskara equation), we obtain:
x = 6.083x10⁻⁴ M
Then: [H⁺] = [C₆H₅COO⁻] = 6.083x10⁻⁴ M
[C₆H₅COOH] = C - x = 3.98x10⁻³ M
pH = -Log [H⁺] = 3.22
Answer:
839 g
Explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 81.97 209.94
NaAlO₂ + … ⟶ Na₃AlF₆ + …
Mass/g: 2150
1. Calculate the <em>moles of Na₃AlF₆
</em>
Moles of Na₃AlF₆ = 2150 × 1/209.94 Do the operation
Moles of Na₃AlF₆ = 10.24 mol Na₃AlF₆
2. Calculate the <em>moles of NaAlO</em>₂
The molar ratio is 1 mol NaAlO₂:1 mol Na₃AlF₆
Moles of NaAlO₂ = 10.24 × 1/1 = 10.24 mol NaAlO₂
3. Calculate the <em>mass of NaAlO₂
</em>
Mass of NaAlO₂ = 10.24 × 81.97 Do the multiplication
Mass of NaAlO₂ = 839 g
