Answer:
12 in the first option bro
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
-5 and 20
Step-by-step explanation:
-5 + 20 = 15
-5 * 20 = -100
Answer: its b
Step-by-step explanation:
Step-by-step explanation:
Given,
Perimeter of the rectangle = 200cm
Breadth of the rectangle = 10 cm
Therefore, by the problem
=> 2(l+b) = 200cm
=> 2(l + 10) = 200cm

=> l + 10 = 100
=> l = 100 - 10
=> l = 90
<u>Hence, required length othe rectangle is 90 cm (Ans)</u>