Answer:
x = 10
The both line crosses with a little hyphen, meaning those are same
Answered by GAUTHMATH
The ordered pair that makes both inequalities true is (4,0).
we have
y<3x-1 ----> inequality A
y > –x + 4----> inequality B
we know that
If an ordered pair is a solution to the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
Inequality A
0<3(4)-1 ----> is true
Inequality B
0> –4 + 4 ----> is true
<h3>What is inequality?</h3>
A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.
So, The ordered pair makes both inequalities true
case 2) (1,2)
Inequality A
2< 3(1) – 1
2<3-1
2<2----> is not true
So the ordered pair does not make both inequalities true
case 3) (0,4)
Inequality A
0 < 3(4) – 1
0<12-1
0<11 ----> is not true
So, the ordered pair does not make both inequalities true
case 4) (2,1)
Inequality A
1< 3(2) – 1
1<6-1
1<5----> is true
Inequality B
![1\geq -2+4](https://tex.z-dn.net/?f=1%5Cgeq%20-2%2B4)
----> is not true
So the ordered pair does not make both inequalities true.
To learn more about the inequalities visit:
brainly.com/question/24372553
#SPJ1
5*5 is 25 / 1 is 25
25*7 is 175*2 is 350
350+11 is 361
361+55 is 416
416-2 is 414
414 is your answer
Step-by-step explanation:
![\text{The principal square root}:\\\\\sqrt{a}=b\iff a^2=b\ \text{for}\ a\geq0\ \text{and}\ b\geq0.\\\\\text{The square root:}\\\\\sqrt{a}=b\iff b^2=a\ \text{for}\ a\geq0\\===================](https://tex.z-dn.net/?f=%5Ctext%7BThe%20principal%20square%20root%7D%3A%5C%5C%5C%5C%5Csqrt%7Ba%7D%3Db%5Ciff%20a%5E2%3Db%5C%20%5Ctext%7Bfor%7D%5C%20a%5Cgeq0%5C%20%5Ctext%7Band%7D%5C%20b%5Cgeq0.%5C%5C%5C%5C%5Ctext%7BThe%20square%20root%3A%7D%5C%5C%5C%5C%5Csqrt%7Ba%7D%3Db%5Ciff%20b%5E2%3Da%5C%20%5Ctext%7Bfor%7D%5C%20a%5Cgeq0%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![\text{If you want the principal square root (arithmetic square root):}\\\\\sqrt{225}=15\ \text{because}\ 15^2=225\\\\\text{If you want square root (algebraic square root):}\\\\\sqrt{225}=\pm15\ \text{because}\ (-15)^2=225\ \text{and}\ 15^2=225](https://tex.z-dn.net/?f=%5Ctext%7BIf%20you%20want%20the%20principal%20square%20root%20%28arithmetic%20square%20root%29%3A%7D%5C%5C%5C%5C%5Csqrt%7B225%7D%3D15%5C%20%5Ctext%7Bbecause%7D%5C%2015%5E2%3D225%5C%5C%5C%5C%5Ctext%7BIf%20you%20want%20square%20root%20%28algebraic%20square%20root%29%3A%7D%5C%5C%5C%5C%5Csqrt%7B225%7D%3D%5Cpm15%5C%20%5Ctext%7Bbecause%7D%5C%20%28-15%29%5E2%3D225%5C%20%5Ctext%7Band%7D%5C%2015%5E2%3D225)
Answer:
![V= 2x^3](https://tex.z-dn.net/?f=V%3D%202x%5E3)
The volume is 128cm^3
Step-by-step explanation:
Given
![Cubes = 2](https://tex.z-dn.net/?f=Cubes%20%3D%202)
![Sides = 4cm](https://tex.z-dn.net/?f=Sides%20%3D%204cm)
Required
Determine an expression for its volume
Find the volume
Volume of a cube is:
![Volume = x^3](https://tex.z-dn.net/?f=Volume%20%3D%20x%5E3)
Where x represents the length of a side
So, volume of 2 cubes would be:
![V= x^3 + x^3](https://tex.z-dn.net/?f=V%3D%20x%5E3%20%2B%20x%5E3)
![V= 2x^3](https://tex.z-dn.net/?f=V%3D%202x%5E3)
Solving (b): Volume when x = 4
Substitute 3 for x in ![V= 2x^3](https://tex.z-dn.net/?f=V%3D%202x%5E3)
![V = 2 * 4^3](https://tex.z-dn.net/?f=V%20%3D%202%20%2A%204%5E3)
![V = 2 * 64](https://tex.z-dn.net/?f=V%20%3D%202%20%2A%2064)
![V = 128](https://tex.z-dn.net/?f=V%20%3D%20128)
<em>Hence, the volume is 128cm^3</em>