which shows the equation in point-slope form of the line passing through the given point with the given slope. (0,5), m=1/3

Is the simplified form of 2-3 + 3.3 rational? Yes No

N76 [4]

Answer:

YES IT IS

Step-by-step explanation:

2-3 + 3.3

= -1 + 3.3

= -4.3

We learn that:

Rational number: rational number is the number that can be written as a/b (a and b would be intergers and b is not equal to 0). Rational number would be most of numbers we use in out life, except Square root and Pi number.

In this case, -4.3 can be write as -43/10

So YES it would be a rational number

Hope this helped :3

6 0

3 years ago

Can someone please help me with this | | |

Ede4ka [16]

The answer could be 45 but I'm not entirely sure

7 0

2 years ago

Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.

Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If $x + \dfrac{1}{x}$ is an integer

∴ $\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

$x + \dfrac{1}{x}$

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}$

By simplification of the cube of the given integer expressions, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$

Therefore, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}$

By rearranging, we get;

$x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )$

Given that $x + \dfrac{1}{x}$ is an integer, from the closure property, the product of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3$ is an integer and $3\cdot \left (x + \dfrac{1}{x} \right )$ is also an integer

Similarly the sum of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

$\therefore x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer.

4 0

3 years ago

Find the slope of the line that passes through the points (-1, -2) and (-9, -2)

kodGreya [7K]

Slope = change in Y / change in x

Slope = (-2 - -2) / (-9 - -1)

Simplify:

Slope = 0/-8 = 0

Slope = 0

4 0

3 years ago

Which of the following is an arithmetic sequence? 00.2.4.6. 01.24.8. 0 1.4.8. 13....

Ahat [919]

Answer:

(A.) 00,2,4,6

Step-by-step explanation:

00+2=2

2+2=4

2+4=6

Each number is added by the same number, 2, so this is the arithmetic sequence.

6 0

2 years ago

which shows the equation in point-slope form of the line passing through the given point with the given slope. (0,5), m=1/3​

which shows the equation in point-slope form of the line passing through the given point with the given slope. (0,5), m=1/3