Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation
3x+2y=16
3x+2(3x-10)=16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4
sub back
y=3x-10
y=3(4)-10
y=12-10
y=2
x=4
y=2
(4,2) is soluiton
Answer:
4/9
Step-by-step explanation:
(2/3)^2
(2/3) x (2/3)
2 x 2 is 4
3 x 3 is 9
4/9
Answer:
Your answer is c
Step-by-step explanation:
the two inequalities are x =< 1 and x =>2 which is shown by the number line in option c
For the answer to the question above, I'll provide my solutions to my answers for the problem below.
(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)
(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)
(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5
−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5
−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5
(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)
−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= <span><span><span><span><span>−<span><span>6x4</span>y</span></span>−<span><span>2x3</span>y2</span></span>+<span><span>9x2</span>y3</span></span>−<span>3xy4</span></span>+y5</span>
I hope this helps
Answer:
There are infinite solutions because they are the same equation
2D + 1G = 12
and
4D + 2G = 24 (divide by 2) 2D + G = 12
2D + 1G = 12 is the same as 2D + 1G = 12
