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kenny6666 [7]
3 years ago
11

What is the probability that a randomly selected student is a Junior who takes the bus

Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:1/5

Step-by-step explanation:

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HURRY PLEASE I NEED THIS SOON
otez555 [7]

Answer:

option 4 and 6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. How far does a car travel if it's 16-inch wheel rotates 3 times?<br><br><br>HELP!​
Nataly_w [17]

\textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=16 \end{cases}\implies C=16\pi \implies \stackrel{\textit{3 times that much}}{C=48\pi \implies} C\approx \underset{inches}{150.8}

6 0
3 years ago
In the diagram, lines AB , CD, and EF intersect at G
Ghella [55]

Answer:

D. 70°

Step-by-step explanation:

Given:

m<DGB = 35°

m<CGF = 75°

Required:

m<AGE

SOLUTION:

m<EGD = m<CGF (vertical angles are congruent)

m<EGD = 75°

m<AGE + m<EGD + m<DGB = 180° (angles on a straight line)

m<AGE + 75° + 35° = 180° (substitution)

m<AGE + 110° = 180°

Subtract 110 from each side of the equation

m<AGE = 180° - 110°

m<AGE = 70°

6 0
3 years ago
What is the value of x? Enter your answer, as a decimal, in the box.<br><br> ___ cm
lora16 [44]

Answer

50.6

Step-by-step explanation:

I'm not sure how to do it, but I took the quiz and it said this was the correct answer


6 0
3 years ago
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
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