Since both trapezoids are similar, so LMNO is a scaled version of QRST by some magnitude
so we can easily use the concept of ratios to find x
in other words: x÷2=6÷5
so x=6×2÷5=12/5=2.4
x=2.4
P = 2(L + W)
L = W + 5
A = 4P + 2
P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10
A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42
A = L * W
A = W(W + 5)
A = W^2 + 5W
W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0
W - 14 = 0
W = 14 <==
L = W + 5
L = 14 + 5
L = 19 <==
P = 2(19 + 14)
P = 2(33)
P = 66
A = L * W
A = 19 * 14
A = 266
answer : length = 19, width = 14....perimeter = 66....area = 266
Answer:
D
Step-by-step explanation:
correct answer, thanks for 15 pts
Sense this string would only be 11 (in), and we are cutting it into 3 pieces, this would show us that we would then be dividing the 11 (in) string into 3 pieces. The expression would be below.
1. Remove parentheses
-3x^2 + x^4 + x + 2x^4 - 7 + 4x
2. Collect like terms
-3x^2 + (x^4 + 2x^4) + (x + 4x) - 7
3. Simplify
-3x^2 + 3x^4 + 5x - 7
