Answer:
x=25/6
Step-by-step explanation:
3x+11=9x-14
11=6x-14
25=6x
x=25/6
Somebody else had asked this question and they said it was 35 so your best bet is to go with 35
Answer:
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C
Step-by-step explanation:
∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗
Let 1st=arctan(x)
And 2nd=1
∫▒〖arctan(x).1 dx=arctan(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗
As we know that
derivative of arctan(x)=1/(1+x^2 )
∫▒〖1 dx〗=x
So
∫▒〖arctan(x).1 dx=arctan(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1
Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now
Let 1+x^2=u
du=2xdx
Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get
1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)
1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)
1/2 ∫▒(2xdx/u) =1/2 ln(u)+C
1/2 ∫▒(2xdx/u) =1/2 ln(1+x^2 )+C
Putting values in Eq1 we get
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C (required soultion)
Apothem is the height of a triangel formed by two consecutive vertices with the center. the are of this triangle = 1/2 s 8 = 4s
there area 12 such triangles in the regular 12 side polygon
So area = 12 * 4 s = 48 s
Full Question:
Find the volume of the sphere. Either enter an exact answer in terms of π or use 3.14 for π and round your final answer to the nearest hundredth. with a radius of 10 cm
Answer:
The volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³
Step-by-step explanation:
Given
Solid Shape: Sphere
Radius = 10 cm
Required
Find the volume of the sphere
To calculate the volume of a sphere, the following formula is used.
V = ⅓(4πr³)
Where V represents the volume and r represents the radius of the sphere.
Given that r = 10cm,.all we need to do is substitute the value of r in the above formula.
V = ⅓(4πr³) becomes
V = ⅓(4π * 10³)
V = ⅓(4π * 10 * 10 * 10)
V = ⅓(4π * 1,000)
V = ⅓(4,000π)
The above is the value of volume of the sphere in terms of π.
Solving further to get the exact value of volume.
We have to substitute 3.14 for π.
This gives us
V = ⅓(4,000 * 3.14)
V = ⅓(12,560)
V = 4186.666667
V = 4186.67 ---- Approximated
Hence, the volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³
