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3 years ago

- 3/4q = 12 What number does q equal?

2 answers:

5 0

If you would like to know what number does q equal, you can calculate this using the following steps:

- 3/4 * q = 12 /*(- 4/3)
q = 12 * (- 4/3)
q = - 12 * 4 / 3
q = - 16

The correct result would be - 16.

drek231 [11]3 years ago

4 0

-3/4q = 12

proportion = a/b = cd where: ad = bc
a = -3 ; b = 4q ; c = 12 ; d = 1

do cross multiplication:

-3/4q = 12/1
-3*1 = 12*4q
-3 = 48q
q = -3/48 or - 0.0625

to check:
-3/4q = 12
-3/4(-0.0625) = 12
-3/-0.25 = 12
12 = 12

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Two events E1 and E2 are called independent if p(E1 â© E2) = p(E1)p(E2). For each of the following pairs of events, which are su

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Since, If a coin is tossed three times,

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a) $E_1$ : tails comes up with the coin is tossed the first time;

$E_1$ = { TTT, THH, THT, TTH }

$E_2$ : heads comes up when the coin is tossed the second time.

$E_2$ = { THT, HHH, THH, HHT }

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Similarly, $P(E_2)=\frac{1}{2}$

⇒ $P(E_1)\times P(E_2)=\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}$

Since, $E_1\cap E_2$ = { THH, THT }

$n(E_1\cap E_2) = 2$

⇒ $P(E_1\cap E_2) = \frac{n(E_1\cap E_2)}{n(S)}= \frac{2}{8}=\frac{1}{4}$

Thus, $P(E_1\cap E_2)=P(E_1)\timesP(E_2)$

Therefore, $E_1$ and $E_2$ are independent events.

B) $E_1$ : the first coin comes up tails

$E_1$ = { TTT, THH, THT, TTH }

$E_2$ : two, and not three, heads come up in a row

$E_2$ = { HHT, THH }

Thus, $n(E_1)=4$

⇒ $P(E_1)=\frac{n(E_1)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

Similarly, $P(E_2)=\frac{1}{4}$

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Since, $E_1\cap E_2$ = { THH }

$n(E_1\cap E_2) = 1$

⇒ $P(E_1\cap E_2) = \frac{n(E_1\cap E_2)}{n(S)}= \frac{1}{8}$

Thus, $P(E_1\cap E_2)=P(E_1)\timesP(E_2)$

Therefore, $E_1$ and $E_2$ are independent events.

C) $E_1$ : the second coin comes up tails;

$E_1$ = { HTH, HTT, TTT, TTH }

$E_2$ : two, and not three, heads come up in a row

$E_2$ = { HHT, THH }

Thus, $n(E_1)=4$

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Similarly, $P(E_2)=\frac{1}{4}$

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Therefore, $E_1$ and $E_2$ are dependent events.

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3 years ago