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4 years ago

Jack jumps 40 times per 4 minutes. How many times does he jump per 1 minute?

Mathematics

1 answer:

nirvana33 [79]4 years ago

8 0

Answer:

10 jumps/minute

Step-by-step explanation:

Find the unit rate:

40 jumps

---------------- = 10 jumps/minute

4 minutes

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27 divided by 53 minus 6 plus 53 times -2 squared

mamaluj [8]

Answer:

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Step-by-step explanation:

Considering the expression

27 divided by 53 minus 6 plus 53 times -2 squared

Which can be written as

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

So, solving the expression

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{27}{53}-6-53\cdot \:2^2$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:6=\frac{6\cdot \:53}{53}$

$=-\frac{6\cdot \:53}{53}+\frac{27}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-6\cdot \:53+27}{53}$

$=\frac{-291}{53}$ ∵ $-6\cdot \:53+27=-291$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-2^2\cdot \:53-\frac{291}{53}$

$=-212-\frac{291}{53}$ ∵ $53\cdot \:2^2=212$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:212=\frac{212\cdot \:53}{53}$

$=-\frac{212\cdot \:53}{53}-\frac{291}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-212\cdot \:53-291}{53}$

$=\frac{-11527}{53}$ ∵ $-212\cdot \:53-291=-11527$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{11527}{53}$

Therefore,

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Keywords: algebraic expression

Learn more about solving algebraic expression from brainly.com/question/4687406

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8 0

4 years ago

Triple the difference of 100 and double

kvv77 [185]

Answer:

Step-by-step explanation:

3(100 - 2x) = 36x + 6

300 - 6x = 36x + 6

50 - x = 6x + 1

7x = 49

x = 7.

8 0

3 years ago

Is y=(x/3)-12^3 a linear or nonlinear equation

creativ13 [48]

Linear equation.........

7 0

3 years ago

Find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -Si (Show all work to earn credit.)

antoniya [11.8K]

Answer: The required polynomial of lowest degree is $p(x)=x^3-2x^2+25x-50$

Step-by-step explanation: We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.

We know that

if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).

So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.

Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.

This implies that (x - 5i) is also a factor of the given polynomial.

Therefore, the polynomial of lowest degree (three) with real coefficients having zeroes of 2 and -5i is given by

$p(x)=(x-2)(x+5i)(x-5i)\\\\\Rightarrow p(x)=(x-2)(x^2-25i^2)\\\\\Rightarrow p(x)=(x-2)(x^2+25)\\\\\Rightarrow p(x)=x^3-2x^2+25x-50$

Thus, the required polynomial of lowest degree is $p(x)=x^3-2x^2+25x-50$

4 0

4 years ago

Give two ways to write each algebraic expression in words. 4+×

KATRIN_1 [288]

Answer:

the sum of 4 and a number

4 plus a number

4 0

3 years ago