Answer:
<h3><em>
0.19m/s</em></h3>
Explanation:
velocity is the change in displacement of a body with respect to time. Given the displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t², where t is the time in seconds, instantaneous velocity is expressed by differentiating the displacement with respect to time
Velocity = dd/dt
Velocity = -0.65 + 2(0.21)t²⁻¹
Velocity = -0.65 + 0.42t
The instantaneous velocity of the block when t = 2.0 s can be gotten by substituting t = 2.0s into the expression above:
Velocity = -0.65 + 0.42(2)
Velocity = -0.65 + 0.84
Velocity = 0.19
<em>Hence the instantaneous velocity of the block when t = 2.0 s is 0.19m/s</em>
The acceleration of the rocket will be "56.2 m/s²".
According to the question,
The initial speed during launch,
The speed at fuel running out point,
= 375 m/s
Height,
= 1250 m
As we know,
→ 
or,
→ 
By putting the values, we get
→ 
→ 
→ 
Thus the above solution is correct.
Learn more:
brainly.com/question/11038449
Answer:
Height as seen by the professor = 38.2 m
Explanation:
Angle of throw = θ = 69°
Velocity of throw = v
X component of velocity = v₁ = v cos 69 = 0.3584 v m/s
Vertical component of the velocity = v₂ = v sin 69 = 0.9336 v m/s
v₂ / v₁ = tan 69 = 2.605
v₂ = 2.605 v₁.
Professor sees as if the x component of velocity =0
v (as seen by professor) + v' = 0
=> v as seen by professor = -v' = -10.5 m/s
This shows that y component of the ball's velocity is 2.605 times its x component of velocity.
with respect to the professor, there is only y component of velocity.
v₂' =v₂ = 2.605 ( -10.5) = 27.4 m/s.
Height as seen by the professor = (27.4)² / 2(9.8) = 38.2 m
Answer:
0 degrees
Explanation:
this is because when the light ray hits a surface a medium at 90 degrees then the angle of incidence = 0 , thus light doesn't bend when it enters the medium, no bending means angle of refraction is 0 degrees
hope this helps ,please mark it
