Answer:
The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
Explanation:
Given that,
Mass = 2.15 kg
Distance = 0.0895 m
Amplitude = 0.0235 m
We need to calculate the spring constant
Using newton's second law

Where, f = restoring force


Put the value into the formula


We need to calculate the kinetic energy of the mass
Using formula of kinetic energy

Here, 

Here, 


Put the value into the formula


Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.
*heat transfer energy, As it always flow from higher temperature to lower temperature till it reach the thermal equilibrium.
example: -friction.
- collisions.
- the hot cup which's hotter than your hand✋will transfer heat in your hand. and a cold piece of ice which's colder than your hand to causing the heat transfer out of your hand .
*temperature ️ depends on the move of particle and we have a different shape of motion like:
translational motion.
rotational motion.
vibrational motion.
when the temperature:
increases it has more kinetic energy and faster moving particles and the object expanded which known as (thermal expansion).
decreases it has less kinetic energy and slower moving particles.
As kinetic energy is 1/2 mV².
example: -the mercury in thermometers.
*Absolute zero :
The theoretical temperature at which substances possess no thermal energy, equal to 0 K, −273.15°C, or −459.67°F.
*specific heat "c" :
is essentially a measure of how thermally insensitive a substance is to the addition of energy.
c=Q/m∆T
where Q is energy .
note water has a higher specific heat, and lower temperature.
*conduction <em><u>example</u></em> When the stove is turned on, the skillet becomes very hot due to the conduction of heat from the burner to the skillet.
When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.
If a body is at state of rest or motion, when an unbalanced external force acts on it, its starts moving in the direction of force and magnitude of its velocity or acceleration depends on the magnitude of force applied.
The ball will take 2.551 seconds to reach its peak position.
<h3>How much time will the ball take to land?</h3>
We must know how long the balls are in the air before we can predict where they will fall. It will take 2 seconds for both balls to touch the ground.
<h3>How quickly does a ball drop?</h3>
The falling ball travels a distance of d = 12 9.8 (m/s2) t2, with a speed of v = 9.8 (m/s2) t as a function of time. The ball travels 4.9 m in a second. The falling ball's velocity is v = -9.8 (m/s2) t j, and its position is r = (4.9 m - 12 9.8 (m/s2) t2) j as a function of time.
To know more about balls visit:-
brainly.com/question/19930452
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