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3 years ago

What is the weight of a 75kg. Mass?

Physics

2 answers:

AysviL [449]3 years ago

7 0

W=(75kg)(9.8m/s^2

W = 735N

wariber [46]3 years ago

3 0

Weight = (mass) x (gravity wherever the mass is located)

The weight of a 75 kg mass is about 122 newtons on the Moon,
242 newtons on Mars, and 735.5 newtons on Earth.

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If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he

forsale [732]

The amount of heat needed to increase the temperature of a substance by $\Delta T$ is given by
$Q= mC_s \Delta T$
where m is the mass of the substance, Cs is its specific heat capacity and $\Delta T$ is the increase of temperature.

If we re-arrange the formula, we get
$C_s = \frac{Q}{m \Delta T}$
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
$C_s = \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C$

6 0

3 years ago

Read 2 more answers

Force → F = ( − 8.0 N ) ˆ i + ( 6.0 N ) ˆ j acts on a particle with position vector → r = ( 3.0 m ) ˆ i + ( 4.0 m ) ˆ j . What a

andrey2020 [161]

Explanation:

It is given that,

Force, $F=(-8\ N)i+(6\ N)j$

Position vector, $r=(3i+4j)\ m$

(a) The torque on the particle about the origin is given by :

$\tau=F\times r\\\\\tau=(-8i+6j)\times (3i+4j)\\\\\tau=(-50k)\ N-m$

(b) To find the angle between r and F use dot product formula as :

$F{\cdot} r=|F||r|\ \cos\theta\\\\\cos\theta=\dfrac{F{\cdot} r}{|F| |r|}\\\\\cos\theta=\dfrac{(-8i+6j){\cdot} (3i+4j)}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=\dfrac{-24+24}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=0\\\\\theta=90^{\circ}$

Hence, this is the required solution.

8 0

3 years ago

Read 2 more answers

If a machine increases force it must apply the force over a long distance? True or false

Eduardwww [97]

Answer: The machine must apply the force over a shorter distance. That's because a machine doesn't change the amount of work and work equals force times distance. Therefore, if force increases, distance must decrease

FALSE

HOPE THIS HELPS

4 0

3 years ago

From the three lines in our Displacement vs Time graph, which line represents the highest velocity?

Crazy boy [7]

Answer:

line 3.

Explanation:

5 0

3 years ago

In an amusement-park ride, riders stand with their backs against the wall of a spinning vertical cylinder. The floor falls away

seraphim [82]

Answer:

90.78 rev/min

Explanation:

In first place, we have to do the force balance to determine the minimum angular speed required to avoid slipping. The forces acting here are friction and the force due to circular movement, that is centripetal force. Then, we have:

$f=ma_{c}$

μmg=mRω^2

ω= $\sqrt{\frac{μg}{R} } \\$

Then, replacing the given values in the expression we have the following result:

ω=1.51 rev/s*60s=90.78 rev/min

4 0

3 years ago