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3 years ago

Express x and y in terms of trigonometric ratios of 0.

1 answer:

4 0

SIN(θ) = OPPOSITE / HYPOTENUSE = X / Y
COS(θ) = ADJACENT / HYPOTENUSE = 2 / Y
TAN(θ) = OPPOSITE / ADJACENT = X / 2
CSC(θ) = 1 / SIN(θ) = 1 / (X / Y) = Y / X
SEC(θ) = 1 / COS (θ) = 1 / (2 / Y) = Y / 2
COT (θ) = 1 / TAN(θ) = 1 / (X / 2) = 2 / X
HUNEY, YOU HAVE ALL OF THE VALUES, NOW JUST SOLVE FOR X AND Y THEN...
FOR EXAMPLE:
SIN(θ) = X / Y X = Y * SIN(θ)
COS(θ) = 2 / Y Y = 2 / COS(θ)
TAN(θ) = X / 2 X = 2 * TAN(θ)
SO ON, SO FORTH HUN U GET IT

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The graph on the right shows two angles that share the same terminal side: 45° and -315°

rjkz [21]

Answer:

45 - (-315) = 360

-315 - 45 = -360

7 0

3 years ago

What is the equation of the line that passes through the point (4,0) and has a slope<br> of -2

N76 [4]

Answer: y=-2x+8

Step-by-step explanation: Write a table of values where for every x y goes down 2 to find the y intercept (0,8) so it would be 8. The slope is -2 and that is all you need to write the equation.

8 0

1 year ago

Which of the following are true statements.

Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

$c^{2} =a^{2} +b^{2}$ ----------(1)

Let $c=41$ and $a = 7$ and $b=40$

Put all the value in equation 1.

$41^{2} =7^{2} +40^{2}$

$1681=49+1600$

$1681=1649$

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let $c=20$ and $a = 12$ and $b=16$

$20^{2} =12^{2} +16^{2}$

$400=144+256$

$400=400$

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0

3 years ago

Given b= 4 and c= -5, evaluate b2 - c2.<br> 41<br> -2<br> -9

irina [24]

Answer:

-9

Step-by-step explanation:

b² - c²

= 4² - (-5)²

= 16 - 25

= -9

4 0

3 years ago

There are 22 rows of seats on a concert hall: 23 seats are in the 1st row, 27 seats on the 2nd row, 31 seats on the 3rd row, and

JulijaS [17]

We can model this situation with an arithmetic series.
we have to find the number of all the seats, so we need to sum up the number of seats in all of the 22 rows.

1st row: 23
2nd row: 27
3rd row: 31
Notice how we are adding 4 each time.

So we have an arithmetic series with a first term of 23 and a common difference of 4.

We need to find the total number of seats. To do this, we use the formula for the sum of an arithmetic series (first n terms):

Sₙ = (n/2)(t₁ + tₙ)

where n is the term numbers, t₁ is the first term, tₙ is the nth term

We want to sum up to 22 terms, so we need to find the 22nd term

Formula for general term of an arithmetic sequence:

tₙ = t₁ + (n-1)d,

where t1 is the first term, n is the term number, d is the common difference. Since first term is 23 and common difference is 4, the general term for this situation is

tₙ = 23 + (n-1)(4)

The 22nd term, which is the 22nd row, is

t₂₂ = 23 + (22-1)(4) = 107

There are 107 seats in the 22nd row.

So we use the sum formula to find the total number of seats:

S₂₂ = (22/2)(23 + 107) = 1430 seats

Total of 1430 seats.
If all the seats are taken, then the total sale profit is

1430 * $29.99 = $42885.70

4 0

3 years ago