The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.
Answer:
-16 > n or n < -16
Step-by-step explanation:
First, we can write the inequality and distribute.
-6n-12 > 3(-n+12)
-6n-12 > -3n+36
Get rid of a variable first (it makes solving a lot easier). We can add 6n to both sides.
-6n-12 > -3n+36
<u>+6n +6n</u>
-12 > 3n+36
Now, we can subtract 36 on both sides.
-12 > 3n+36
<u>-36 -36</u>
-48 > 3n
Divide by 3 on both sides.
-48 > 3n
<u>/3 /3</u>
-16 > n or (if it's easier) n < -16
Hope this helps!! Have a wonderful day C:
Answer:
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