Three diagonals can be drawn in a hexagon mmyyy dude.
First, let's factor the equation to make it easier to solve for the intercepts:
f(x) = x² + 12x + 32
f(x) = (x + 8)(x + 4)
To find the x-intercepts of a function, set the y value (f(x)) to 0:
0 = (x + 8)(x + 4)
x = -8, -4
Similarly, to find the y-intercept, set the x values to 0:
f(x) = (0 + 8)(0 + 4)
f(x) = (8)(4)
f(x) = 32
*Note that you can see 32 as the y-intercept in the parabola's original equation
Answer:
x=3
Step-by-step explanation:
10-3x+8x=25
-10 -10
-3x+8x= 15
5x=15
5x/5=15/5
x=3
First, put the numbers in order...very important
301,305,310,317,325,328,345,361,362,394
minimum (smallest number) = 301
Q1 = 310
Q2 (middle number) = (325 + 328)/2 = 653/2 = 326.5
Q3 = 361
maximum (largest number) = 394
Answer:
zero slope
Step-by-step explanation:
