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Gekata [30.6K]
3 years ago
15

Which number has two lines of symmetry? 101 619 33 18

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

33 in middle - and in between I

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find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
The N71-90 virus will give an infected person a mild rash on their arms once the person has 1 billion of the virus cells in thei
Naya [18.7K]

Answer:

  • B. 256

Step-by-step explanation:

<u>Given function:</u>

  • v(h) = 2^(h/4)

<u>It can be rewritten as:</u>

  • v(d) = 2^d, where d- number of divisions

<u>If number of divisions is 8, then:</u>

  • v(8) = 2^8 = 256 virus cells

Correct choice is B

4 0
3 years ago
Read 2 more answers
6. Find how long it takes $600 to double if it is invested at 12%
ioda

Answer:

A = $697.09

Step-by-step explanation:

A = P (1 + r/n)

A = 600 (1 + 0.05/365)

A = $697.09

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3 years ago
FIRST TO ANSWER GETS BRAINLIEST: The average age of one hundred Year 9 students is 14 y 10 m. The average age of one hundred Yea
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Answer:

2) 14 y 2 m

Step-by-step explanation:

Year 9 students: total age= 100* 14 10/12= 1400 +100*5/6= 1483 y 8 m

Year 8 students: total age= 100* 13 6/12= 1350 y

Total age of 200 students: 1483 y 8 m + 1350 y= 2833 y 8 m

Average age= 2833  8/12  ÷ 200= (12*2833+8)/12 ÷ 200 = 34004/(12*200)= 34004/2400= 14  404/2400 ≈ 14 1/6 y= 14 y 2 m

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3 years ago
Help me solve please
Elodia [21]
1. X = 83
2. X = 101
3. X = 24
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3 years ago
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