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Gekata [30.6K]
4 years ago
15

Which number has two lines of symmetry? 101 619 33 18

Mathematics
1 answer:
7nadin3 [17]4 years ago
4 0

33 in middle - and in between I

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Jocelyn got 19 out of 25 questions correct on her test what is the percent of the questions she answered correctly
QveST [7]
Her percentage is 76%
4 0
3 years ago
Read 2 more answers
Solve for x: 2/7(x-2) = 4x
zheka24 [161]

Answer:

2/7(x-2)=4x

(2×x-2×2)/7 = 4x

(2x-4)/7 = 4x

2x-4×(1) = 4x × 7 ( Cross multiply)

2x-4 = 28

2x = 32

2x÷2 = 32÷2

x=16

8 0
3 years ago
HELP! Quick! Test! Will mark brainliest!
Vilka [71]

Answer:

Number of wooden carving = a

Total amount Sam spend = 1,200 + 4a

Total revenue of Sam = 15a

Number of wooden carving make to earn profit $4,300 = 500 carvings

Step-by-step explanation:

Given:

Sales price of each wooden carving = $15

Fixed cost = $1,200

Variable cost = $4 for each

Find:

Number of wooden carving make to earn profit $4,300

Computation:

Part 1

Assume

Number of wooden carving = a

Part 2

Total amount Sam spend = 1,200 + 4a

Part 3

Total revenue of Sam = 15a

Part 4

Total profit of Sam = Total revenue of Sam - Total cost of Sam

4,300 = 15a - [1,200 + 4a]

4,300 = 15a - 1,200 - 4a

11a = 5,500

a = 5,500 / 11

Number of wooden carving make to earn profit $4,300 = 500 carvings

7 0
3 years ago
U 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what
nikdorinn [45]

<u>Answer:</u>

The probability that at most 10 of them will be living with both of their parents is 0.0018

<u>Solution:</u>

Given, US 1995, 70% of all children in the U.S. were living with both parents.  25 children were selected at random in the U.S.,  

We have to find what is the probability that at most 10 of them will be living with both of their parents?  

Now, number of children picked (n) = 25.

Probability to be with parents = 70% = 0.7.

Our condition is 0 ≤ x ≤ 10.

Then, we have to calculate p(0 ≤ x ≤ 10).

We can calculate using binomial cumulative distribution frequency- binomial CDF

Now, p(0 ≤ x ≤ 10) = binomcdf(n, p, x) = binomcdf(25, 0.7, 10) = 0.00177840 ≈ 0.0018.

Hence, the probability is 0.0018

6 0
3 years ago
Compare negative two and three tenths repeating and negative eight thirds using symbols &lt;, &gt;, or =.
Novay_Z [31]

Answer:

-2 < \frac{1}{3} > -\frac{8}{3}

Note:

Three-tenths reapeating is \frac{1}{3}

6 0
2 years ago
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