Answer:
table; occur; tally mark
Step-by-step explanation:
You would use a table to keep track of a distribution of data. You would have to wait for such data to occur. You could use tally marks to keep track to the data.
Hope this helps.
Sorry if it's wrong though.
Answer:
x = 5
Step-by-step explanation:
√(2x − 1) + 2 = x
√(2x − 1) = x − 2
2x − 1 = (x − 2)²
2x − 1 = x² − 4x + 4
0 = x² − 6x + 5
0 = (x − 1) (x − 5)
x = 1 or 5
Check for extraneous solutions.
√(2(1) − 1) + 2 = 1
√(1) + 2 = 1
3 = 1
No solution
√(2(5) − 1) + 2 = 5
√(9) + 2 = 5
5 = 5
x = 5
Answer:
Step-by-step explanation:
Look for the GCF and then divide every term by the GCF to see what remains
(9) 5a - 25 ( GCF is 5 so take out 5 and divide every term by 5)
5(a-5)
(10) 28 - 7x ( GCF is 7 so take out 7 and divide every term by 7)
7(4-x)
(11) 12z + 28 - 7z - 3= (combine terms) =
5x+25( GCF is 5 so take out 5 and divide every term by 5)
5(x+5)
F(x) = 3x² + 6x - 1
The graph is a parabola open upward (a= 3>0) with a minimum.
Calculate the vertex:
x = -b/2a → x = -6/(2.3) = -1. Then the axis of symmetry is x = - 1
Now to calculate the minimum, plugin the value of x:
y = 3x² + 6x - 1
y = 3(-1)² + 6(-1) -1
y= 3 - 6 -1 and y = - 4,
Ten the vertex (minimum) is at (-1,- 4)