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Sever21 [200]
3 years ago
5

farmer bob is trying to figure out how much space he has for his garden. If the sides of the garden are 10 ft and 50 ft, what is

the area of his garden
Mathematics
2 answers:
aleksley [76]3 years ago
7 0

The area of the garden is 500...

10*50= 500


SIZIF [17.4K]3 years ago
6 0

area = length times width

A = l* w

A = 10 * 50

A = 500 ft ^2


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Read 2 more answers
No chi-square The principal in Exercise 7 also
larisa [96]

The random sample of the students is an illustration of sampling

The chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

<h3>How to determine the reason chi square is not appropriate?</h3>

The dataset is given as:

Monday        34

Tuesday       29

Wednesday   32

Thursday        28

Friday             19

The variable of the above dataset is a not a categorical dataset.

One of the conditions of the chi-square test for goodness of fit test is that the variable under study must be categorical.

Hence, the chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

Read more about chi-square test at:

brainly.com/question/19959558

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2 years ago
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

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