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3 years ago

5

farmer bob is trying to figure out how much space he has for his garden. If the sides of the garden are 10 ft and 50 ft, what is

the area of his garden

2 answers:

aleksley [76]3 years ago

7 0

The area of the garden is 500...

10*50= 500

SIZIF [17.4K]3 years ago

6 0

area = length times width

A = l* w

A = 10 * 50

A = 500 ft ^2

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Factor completely 2x^3 + 14x^2 + 6x + 42.

masha68 [24]

Hello,

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=(x+7)(2x²+6)
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3 years ago

Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En

Agata [3.3K]

Answer:

Sin theta = 12/13

Step-by-step explanation:

From the question;

Cot theta = 5/12

Kindly recall;

Cot theta = 1/ tan theta

Hence, tan theta = 12/5

Mathematically

tan theta= opposite/adjacent

to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

h^2 = 12^2 + 5^2

h^2 = 144 + 25

h^2 = 169

h = √169

h = 13

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5 0

2 years ago

Use a trigonometric function to find the value of x

Alex17521 [72]

(180-30)/2 would be the equation and the answer is 150/2

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3 years ago

The fish population in a pond evolves according to the logistic equation and a percentage of fish are removed for each unitof ti

musickatia [10]

Step-by-step explanation:

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3 years ago

Five thousand tickets are sold at $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a

aksik [14]

Answer:

the expected value of this raffle if you buy 1 ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.

Thus; the amount and the corresponding probability can be computed as:

Amount Probability

$500 -$1 = $499 1/5000

$300 -$1 = $299 3/5000

$50 - $1 = $49 5/5000

$5 - $1 = $4 20/5000

-$1 1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is as follows:

$E(x) = \sum x * P(x)$

$E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))$

$E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))$

$E(x) = (0.3442 -0.9942 )$

$\mathbf{E(x) = -0.65}$

Thus; the expected value of this raffle if you buy 1 ticket = -0.65

7 0

3 years ago