1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio [31]
2 years ago
15

Need help with Algebra 2! Thank you! :)

Mathematics
1 answer:
Olin [163]2 years ago
7 0

Answer:

Consider the parent logarithm function f(x) = log(x)

Now,

Let us make transformations in the function f(x) to get the function g(x)

•On streching the graph of f(x) = log(x) , vertically by a factor of 3, the graph of y = 3log(x) is obtained.

•Now, shrinking the graph of y = 3log(x) horizontally by a fctor of 2 to get the grpah of y = 3log(x/2) i.e the graph of g(x)

Hence, the function g(x) after the parent function f(x) = log(x) undergoes a vertical stretch by a factor of 3, and a horizontal shrink by a factor of 2 is

g(x) = 3 log(x/2) (Option-B).

You might be interested in
-3x – 10 = 32Help me I need the answer
Nesterboy [21]

Answer:

<h2><u><em>x = - 14</em></u></h2>

Step-by-step explanation:

-3x – 10 = 32 Help me I need the answer

-3x – 10 = 32

-3x = 32 + 10

-3x = 42

x = 42 :(-3)

x = - 14

-----------------

check

-3 × (-14) - 10 = 32                      (remember pemdas)

42 - 10 = 32

32 = 32

the answer is good

6 0
9 months ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
2 years ago
Heyy! i’ll give brainliest please help
ipn [44]

Answer:

Step-by-step explanation:

Always capitalize the names of the seasons

3 0
2 years ago
Read 2 more answers
Help me. This is hard.... T^T
irina1246 [14]

Answer:

2 Sandwiches

Step-by-step explanation:

j =  - 6s + 38 \\ 26 =  - 6s + 38 \\ 26 - 38 =  - 6s \\  - 12 =  - 6s \\ 2 = s

3 0
2 years ago
Select all the numbers that Logan could multiply by 54,216 to get a product less than 54,216
Svetradugi [14.3K]
Any answer less than one would work, soothe answers are A and D
4 0
2 years ago
Read 2 more answers
Other questions:
  • How do I solve this equation
    10·2 answers
  • cashews cost 4c per packet. mandy buys 4 packets of cashews. how much change does she recieve if she paid with a $20 bill? Give
    8·1 answer
  • A soma do quadrado de um numero com seu quintuplo é igual a zero. qual seu numero
    11·1 answer
  • Can someone help me with this .(let the download load or check in your downloads)
    11·1 answer
  • Can you help me please
    11·1 answer
  • A six sided cube is rolled. find the probability of P (4) as a decimal
    14·1 answer
  • In a set of 1,000 integers from 1 to 1,000, an integer chosen at random on a single trial should be an integer from 1 to 25 abou
    11·1 answer
  • Consider the quadratic expression given below.
    6·1 answer
  • When two 6-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is 8
    11·1 answer
  • Whats 3/5 of 6 hours :/
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!