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topjm [15]
4 years ago
10

(d -10) + (d ÷ 3) for d = 21. explain

Mathematics
1 answer:
julsineya [31]4 years ago
3 0


Substitute the number 21 for all the letter d's:

(21-10) + (21/3) = ?

11 + 7 = 18

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Find the numbers a, b and c if the polynomial x3−18x2+24xb−c is the cube of the binomial x+2a.
mojhsa [17]

Answer:

a=-3\\ \\b=\dfrac{9}{2}\\ \\c=216

Step-by-step explanation:

Use formula

(u+v)^3=u^3+3u^2v+3uv^2+v^3.

Hence,

(x+2a)^3=x^3+3x^2\cdot 2a+3x\cdot (2a)^2+(2a)^3=x^3+6ax^2+12a^2x+8a^3.

This expression is equal to

x^3-18x^2+24bx-c,

so we can equate the coefficients at powers of x:

x^3:\ 1=1\\ \\x^2:\ 6a=-18\Rightarrow a=-3\\ \\x:\ 12a^2=24b\Rightarrow b=\dfrac{9}{2}\\ \\1=x^0:\ 8a^3=-c\Rightarrow c=-8\cdot (-3)^3=216.

6 0
4 years ago
David is fertilizing his garden. The garden is in the shape of a rectangle. Its length Is 15 feet and its width is 13 feet. Supp
Serga [27]

Answer:

He will need 5 bags of fertilizer

Step-by-step explanation:

The area of the field would be 15 x 13 which is 195 square feet . If one bag of fertilizer covers 39 square feet then by dividing 195 by 39 you can come up with the answer; 5 bags

8 0
2 years ago
A wire is first bent into the shape of a square. Each side of the square is 9cm long. Then the wire is unbent and reshaped into
EastWind [94]

Answer:

5 cm

Step-by-step explanation:

the perimeter of a square with sides of 9 cm is 36 cm so the rectangle must have the same perimeter

if the length of the rectangle is 13cm, its opposite side is also 13cm

add 13 + 13 to get 26

let 'n' = width of rectangle

perimeter = 26 + n + n

36 = 26 + 2n

2n = 10

n = 5

8 0
3 years ago
Read 2 more answers
What percent of 51 is 127.5?
kolbaska11 [484]
51 *  \frac{x}{100} = 127.5 
 \\ 
51 * x = 127.5 * 100 \\ 
51*x = 12.750 \\ 
x =  \frac{12.750}{51} \\  \\ 
x = 250 


the percentage is 250
7 0
4 years ago
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
4 years ago
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