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ryzh [129]
3 years ago
11

)Two similar triangles are shown on the following coordinate grid:

Mathematics
2 answers:
DIA [1.3K]3 years ago
5 0

Answer:

d on edge 2020

Step-by-step explanation:

muminat3 years ago
4 0

Answer:

Reflection across the y-axis and a dilation by a factor of 2.

Step-by-step explanation:

Comparing the points from the pre-image, ABC, to the image, A'B'C', we see that both x- and y-coordinates seem to be doubled from the pre-image to the image. However, the sign of the x-coordinates in the image is different; this means that the x-coordinates are negated.  A reflection across the y-axis will negate the x-coordinates.

To double both the x- and y-coordinates, we would then apply a dilation by a factor of 2, as the scale factor gets multiplied by every coordinate.

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Tatiana [17]
It can be solved by factoring or taking the root of both sides.

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7 0
3 years ago
Which of the following equations have complex roots?
goldenfox [79]

9514 1404 393

Answer:

  B.  3x² +2 = 0

Step-by-step explanation:

The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)

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The equation of B can be rewritten as ...

  x² = -2/3

This will have complex roots.

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The discriminants of both equations C and D are positive, so those have only real roots.

  2x² -5x -1   ⇒   d = (-5)² -4(2)(-1) = 33

  3x² -6x -1   ⇒   d = (-6)² -4(3)(-1) = 48

6 0
3 years ago
3x^2 – 8x + 5 = 5x^2
Ghella [55]

Answer:

Step-by-step explanation:

3x^2 -8x +5 = 5x^2\\\\5x^2 - 3x^2 + 8x -5 =0\\\\2x^2 +8x -5 = 0\\\\

a = 2, b = 8, c = -5

x = \frac{-b \pm \sqrt{b^2 -4ac} }{2a}\\\\x = \frac{-8 \pm \sqrt{8^2 - ( 4 \times 2 \times (-5))} }{2 \times 2}\\\\x = \frac{-8 \pm \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{64 +40} }{4} \ , \ x = \frac{-8 - \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{104} }{4} \ , \ x = \frac{-8 - \sqrt{104} }{4}\\\\x = \frac{-8 + \sqrt{4 \times 26} }{4} \ , \ x = \frac{-8 - \sqrt{4 \times 26} }{4}\\\\x = \frac{-8 +2 \sqrt{26} }{4} \ , \ x = \frac{-8 - 2\sqrt{26} }{4}\\\\

x = \frac{-4 + \sqrt{26} }{2} \ , \ x = \frac{-4 - \sqrt{26} }{2}

8 0
3 years ago
a student carres a bag weighing 5kg from the ground floor to his clas on the first floor that is 2m high. the work done by the b
Studentka2010 [4]
The answer is: C 100 J
8 0
3 years ago
Read 2 more answers
Oscar caught a fish that weighed 4 1/6 pounds and then caught another that weighed 6 5/8 pounds. How much more did the second fi
lorasvet [3.4K]

Answer:

The second fish was heavier by almost 2.5 pounds

Step-by-step explanation:

6 5/8 - 4 1/6 = 59/24 = 2 11/24 = 2.458

4 0
3 years ago
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