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3 years ago

11

)Two similar triangles are shown on the following coordinate grid:

2 answers:

DIA [1.3K]3 years ago

5 0

Answer:

d on edge 2020

Step-by-step explanation:

muminat3 years ago

4 0

Answer:

Reflection across the y-axis and a dilation by a factor of 2.

Step-by-step explanation:

Comparing the points from the pre-image, ABC, to the image, A'B'C', we see that both x- and y-coordinates seem to be doubled from the pre-image to the image. However, the sign of the x-coordinates in the image is different; this means that the x-coordinates are negated. A reflection across the y-axis will negate the x-coordinates.

To double both the x- and y-coordinates, we would then apply a dilation by a factor of 2, as the scale factor gets multiplied by every coordinate.

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2 years ago

Are all integers rational numbers?

Snezhnost [94]

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True

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Yes! All integers "are" rational numbers. They can be expressed in the form of p/q.

Hope this helps :D

Don't hesitate asking anything regarding this.

5 0

3 years ago

Read 2 more answers

A soccer ball on the ground is kicked with an initial velocity of 37 feet per second at an elevation angle of 70°. Which

Montano1993 [528]

Answer:

x(t) = 37cos(70o)t and y(t) = –16t2 + 37sin(70o)t

Step-by-step explanation:

6 0

3 years ago

If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e

Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

<em>99 is an outlier of pet group</em>
<em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

$n = 15$

The quartiles positions are:

$Q_1 = \frac{n + 1}{4}$

$Q_1 = \frac{15 + 1}{4}$

$Q_1 = \frac{16}{4}$

$Q_1 = 4th$

$Q_3 = Q_1 \times 3$

$Q_3 = 4th \times 3$

$Q_3 = 12th$

So, we have:

$Q_1 = 4th$

$Q_3 = 12th$

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

$Q_1 = 68$

$Q_3= 79$

The lower and upper limits of the outlier are:

$L = Q_1 - 1.5 \times (Q_3 - Q_1)$

$U = Q_3 + 1.5 \times (Q_3 - Q_1)$

So, we have:

$L = 68 - 1.5 \times (79 - 68)$

$L = 51.5$

$U = 79+ 1.5 \times (79 - 68)$

$U = 95.5$

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0

3 years ago

Question 9 (1 point)

Alex Ar [27]

Answer:

B IS THE ANSWER

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers