Solution:
Given: zj = 3- j2, zz = - 4 + j3
Part a:
zj = 3- j2 = 
zz = - 4 + j3 = 
Part b:
|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60
|z1| = √(3− j2)(3+ j2) = √
13 = 3.60.
Part c:
With the help of part a:
z1z2 = 
Answer:
The slope of the blue line is undefined
Step-by-step explanation:
This is because a vertical line cannot have a numerical value for it's slope. Also, there is no y-intercept
Answer:
(3 - y) & (x - a) are the factors
Step-by-step explanation:
3x-3a+xy-ay
=> 3x - xy - 3a - ay
=> x(3 - y) - a(3 - y)
=> (3 - y)(x - a)