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Hunter-Best [27]
2 years ago
10

-3.5y - 6.2y = - 87.3

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

the answer is 9

Step-by-step explanation:

-3.5y - 6.2y = - 87.3

or, -9.7y = -87.3

or, y = -87.3/-9.7

or, y = 9.

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3 years ago
how much would 600 invested at 8% interest compounded continuously be worth after 3 years? round your answer to the nearest cent
marysya [2.9K]
\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$600\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
t=years\to &3
\end{cases}
\\\\\\
A=600e^{0.08\cdot 3}\implies A=600e^{0.24}
8 0
3 years ago
Rick's lumberyard has 360 yd of fencing with which to enclose a rectangular area. If the enclosed area is x yards​ long, express
cestrela7 [59]

Answer:

180x - x²

Step-by-step explanation:

Since the yard has 360 yd. of fencing, hence the perimeter of Rick's lumberyard has 360 yd.

Given that the yard is x yards long. Let y represent the width of the yard. Hence:

Perimeter of the yard = 2(length + width) = 2(x + y)

Substituting:

360 = 2(x + y)

180 = x + y

y = 180 - x

Therefore the width of the yard is (180 - x) yard.

The area of the yard is the product of the length and the width, hence:

Area (A) = length * width

A = x * (180 - x)

A = 180x - x²

3 0
2 years ago
Two containers filled with water are leaking. Container A leaks at a rate of 1/4 gallon per hour. Container B leaks at a rate of
valina [46]
Container a because 1/4 is 25% and 1/8 is 0.125
7 0
3 years ago
One mole of iron (6 × 1023 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-c
MrMuchimi

Answer:

a) k_{s} = 3.6 N/m ; b) 9.43 * 10¹²; c) 1.18 * 10¹¹; d) 75.08 N/m

Step-by-step explanation:

Length of iron bar = L = 2.7m;

side length of cross section = a = 0.07cm = 0.0007m;

x = 2.7 cm = 0.027m;

m = 100kg;

ρ = 7.87gm/cm³;

da = 2.28 * 10⁻¹⁰m;

a)

Fnet = F - mg

where Fnet = 0

So,

F = mg where F=k_{s}x

k_{s} = mg/x = 100*9.8/0.027

k_{s} = 3.6 N/m

b)

Nchain = Aw/Aa =a²/(da)²

                           = (o.ooo7)²/(2.28 * 10⁻¹⁰)²

                           = 9.43 * 10¹²

c)

Nbond = L/da = 2.7/2.28 * 10⁻¹⁰

                       = 1.18 * 10¹¹

d)

Spring stiffness of wire = ksi = (Nbondk_{s})/Nchain

                                      = [(1.18* 10¹¹)(6*10⁴)]/(9.43 * 10¹²)

                                      = 75.08 N/m

8 0
2 years ago
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