The probability of getting all heads is 1 / 2^6 = 1/64 as there is only 1 event where this happens in a possible 2^6 = 64 events. It is the same as the probability of getting all tails. The probability of getting at least 1 head is 1 - p(all tails) = 63/64.
A. Sixty-two is the written form of the number 62. It is hyphenated.
Answer:
0.1611
Step-by-step explanation:
Uaing the binomial probability relation :
p = 0.5 ; q = 1 - p = 0.5
n = 10
Using the relation :
P(x = x) = nCx * p^x * q^(n-x)
P(x = 7) = 10C7 * 0.5^7 * 0.5^3
P(x = 7) = 0.1172
x = 8 ;
P(x = 8) = 10C7 * 0.5^7 * 0.5^3
P(x =8) = 0.0439
P(x = 7 or x = 8) = 0.1172 + 0.0439 = 0.1611
Answer:
23
Step-by-step explanation:
please mark brainliest
M= 4/5 or the alternative form for m can be 0.8
