1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Makovka662 [10]
3 years ago
5

Daniel’s school is selling tickets to the annual talent show. On the first day of ticket sales, the school sold 8 senior citizen

tickets and 8 child tickets for a total of $136. The school took in $138 on the second day by selling 9 senior citizen tickets and 4 child tickets. What is the price each of one senior citizen ticket and one child ticket?
Mathematics
2 answers:
jekas [21]3 years ago
8 0
The correct answer would be 17.
zavuch27 [327]3 years ago
3 0

Answer:

the answer is 17

Step-by-step explanation:

You divide 8 and 136 and get 17, you multiply 17 and 8 to double check your answer, Hope this helps :P!

You might be interested in
A plane leave an airport and flies due north. (more in photo)
galina1969 [7]

Answer:

104 miles (nearest whole number)

Step-by-step explanation:

Applying Pythagorean theorem which is: c² = a² + b². Where,

c = distance between the two planes = ?

a = distance of the first plane from the airport = 80 - 1 = 79 miles

b = distance of the second plane from the airport = 68 - 1 = 67 miles

c² = 79² + 67²

c² = 10,730

c = √10,730

c = 103.585713

c = 104 miles (nearest whole number)

6 0
2 years ago
In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching
Advocard [28]

Answer:

a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455

b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460

d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)

c = 2.12

e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 8.46 min

Standard deviation = σ = 0.913 min

a) Probability that haul time will be at least 10 min = P(X ≥ 10)

We first normalize/standardize 10 minutes

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

To determine the required probability

P(X ≥ 10) = P(z ≥ 1.69)

We'll use data from the normal distribution table for these probabilities

P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)

= 1 - 0.95449 = 0.04551

The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455

b) Probability that haul time will exceed 15 min = P(X > 15)

We first normalize 15 minutes.

z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16

To determine the required probability

P(X > 15) = P(z > 7.16)

We'll use data from the normal distribution table for these probabilities

P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)

= 1 - 1.000 = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)

We normalize or standardize 8 and 10 minutes

For 8 minutes

z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50

For 10 minutes

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

The required probability

P(8 < X < 10) = P(-0.50 < z < 1.69)

We'll use data from the normal distribution table for these probabilities

P(8 < X < 10) = P(-0.50 < z < 1.69)

= P(z < 1.69) - P(z < -0.50)

= 0.95449 - 0.30854

= 0.64595 = 0.6460 to 4 d.p.

d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?

98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.

Let the lower limit be x'

Let the upper limit be x"

P(x' < X < x") = 0.98

P(X < x') = 0.01

P(X < x") = 0.99

Let the corresponding z-scores for the lower and upper limit be z' and z"

P(X < x') = P(z < z') = 0.01

P(X < x") = P(z < z") = 0.99

Using the normal distribution tables

z' = -2.326

z" = 2.326

z' = (x' - μ)/σ

-2.326 = (x' - 8.46)/0.913

x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34

z" = (x" - μ)/σ

2.326 = (x" - 8.46)/0.913

x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58

Therefore, P(6.34 < X < 10.58) = 98%

8.46 - c = 6.34

8.46 + c = 10.58

c = 2.12

e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

This is a binomial distribution problem because:

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)

- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)

Probability that at least one of them exceeds 10 mins = P(X ≥ 1)

= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

= 1 - P(X = 0)

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 4 haul times are independently selected

x = Number of successes required = 0

p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455

q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545

P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044

P(X ≥ 1) = 1 - P(X = 0)

= 1 - 0.83004900044 = 0.16995099956 = 0.1700

Hope this Helps!!!

7 0
3 years ago
Determine the probability of having 2 girls and 3 boys in a 5-child family assuming boys and girls are equally likely.
Andrew [12]
The correct answer is 5/16.
5 0
2 years ago
1.2 as a fraction with a denominator of 8
Aleks04 [339]
The answer is 1 whole and 1 /18. Hope this helps!
3 0
3 years ago
An oil tanker empties at 3.5 gallons per minute. Convert this rate to cups per second. Round to the nearest tenth.
ss7ja [257]
If given ratio is 3.5 gallons per minute and we want to cups per second we can do this knowing that 
1 gallon= 16cups
1min = 60sec
ratio=3.5\frac{gallon}{minute}=3.5* \frac{16cups}{60 seconds}  =3.5*0.266=0.933 \frac{cups}{sec}
Its the result
4 0
3 years ago
Other questions:
  • Please help you will get 20 points and explain your answer please
    10·2 answers
  • Two students in your class, Wilson and Alexis, are disputing a function. Wilson says that for the function, between x = –1 and x
    13·1 answer
  • For several years, Graham has gathered data on students who own a computer and on their performance on a typing-speed test. He c
    8·1 answer
  • A cedar board is 2 inches long and 8 feet long. You will need to cut down the length of the board into 1 1/3 inches long. How ma
    14·1 answer
  • How can you determine the coordinates of any image that is dilated with the center of dilation at the origin without graphing? E
    14·1 answer
  • Volume problem. Will give brainliest
    9·1 answer
  • The booster club sold 36,276 tickets on Friday, 34,012 tickets on Saturday, and 29,879 tickets on Sunday. If you were going to f
    8·2 answers
  • True or false every whole number is a multiple of 1?
    12·1 answer
  • Use substitution to solve the following system of equations. What is the value of y?
    7·1 answer
  • Add. 3x^2 -5x +1 + 2x^2 +9x -6
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!