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igomit [66]
3 years ago
6

What is an angle that is adjacent to CED?

Mathematics
1 answer:
devlian [24]3 years ago
8 0
I think BEA is adjacent to it
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The perimeter of a “STOP” sign is 100 in. What is the length of each side?
Brums [2.3K]
Each side is 12.5 inches
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1 year ago
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Solve (2x-1/4)+(x/3)=2<br> Please provide a step by step with explanation
andrew11 [14]

Answer:

x = 27/10 or x = 2.7

Step-by-step explanation:

Step 1: Get rid of the denominator.

LCD of 4 & 3: 12

Multiply both sides by 12.

12 ( 2x - 1 / 4 ) + 12 ( x / 3 ) = 12 (2)

Reduce the numbers.

3 ( 2x - 1) + 4x = 24

Step 2: Distribute.

6x - 3 + 4x = 24

Step 3: Collect like terms.

6x + 4x = 24 + 3 ( - 3, the sign change when moved to the other side)

10x = 27

Step 4: Solve for x.

Multiply both sides by 10.

10x / 10 = 27 / 10 (the 10 cancels out)

x = 27 / 10 or x = 2.7

Answer: x = 27 / 10 or x = 2.7

7 0
2 years ago
Cora chose to have her birthday party
kramer

$35, sorry if I’m wrong

6 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
a 2-month membership to the gym cost $125 jim would like to be a member for 8 months what is the total amount he will pay for 8
Natasha2012 [34]

Answer:

500

Step-by-step explanation:

125 x 4

8 0
3 years ago
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