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igomit [66]
3 years ago
6

What is an angle that is adjacent to CED?

Mathematics
1 answer:
devlian [24]3 years ago
8 0
I think BEA is adjacent to it
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Hi there! please help with this.
USPshnik [31]

Answer:

Step-by-step explanation:

I dont know wish I could help, srry.

5 0
3 years ago
The midpoint of AD is C. The midpoint of AC is B. If A is at (-10,4) and D is at (2,12), find the coordinates of B.
Nata [24]

does this help

The coordinates of D are (-3, -7)

First we need to find the coordinates of B. In order to do that we simply take the average of the two points that make up the segment for which it is the midpoint (A and C).

Average of x's

-9 + -1 = -10/2 = -5

Average of y's

-4 + 6 = 2/2 = 1

Therefore, the coordinates of B are (-5, 1).

Now we can find D by noting the E will be the average of B and D. So we can use the average equation to determine the values of D.

Average of x's

(B + D)/2 = E

(-5 + D)/2 = -4

-5 + D = -8

D = -3

Average of y's

(B + D)/2 = E

(1 + D)/2 = -3

1 + D = -6

D = -7

Now we know the coordinates of D to be (-3, -7)

7 0
3 years ago
If lines p and q are perpendicular and the slope of line p is 2 what is th slope of line q
miss Akunina [59]

perpendicular lines are negative reciprocals of each other so if line p has a slope of 2 then line q has a slope of -1/2.

:)))

5 0
3 years ago
What is a counterexample of the statement “all square roots are irrational”
skad [1K]

Rather than trying to guess and check, we can actually construct a counterexample to the statement.

So, what is an irrational number? The prefix "ir" means not, so we can say that an irrational number is something that's not a rational number, right? Since we know a rational number is a ratio between two integers, we can conclude an irrational number is a number that's not a ratio of two integers. So, an easy way to show that not all square roots are irrational would be to square a rational number then take the square root of it. Let's use three halves for our example:

\sqrt{(\frac{3}{2})^2}=\\\sqrt{\frac{9}{4}}=\\\frac{3}{2}

So clearly 9/4 is a counterexample to the statement. We can also say something stronger: All squared rational numbers are not irrational number when rooted. How would we prove this? Well, let \frac{a}{b} be a rational number. That would mean, \frac{a^2}{b^2}, would be a/b squared. Taking the square root of it yields:

\sqrt{\frac{a^2}{b^2}}}=\\ \frac{\sqrt{a^2}}{\sqrt{b^2}}=\\ \frac{a}{b}

So our stronger statement is proven, and we know that the original claim is decisively false.

3 0
3 years ago
Write the number that is 6 less then 8000​
Katen [24]

Answer:

8000-6=7994 is the required number

3 0
3 years ago
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